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Mrrafil [7]
3 years ago
5

A man, a distance d=3~\text{m}d=3 m from a target, throws a ball at an angle \theta= 70^\circθ=70 ​∘ ​​ above the horizontal. If

the initial speed of the ball is v=5~\text{m/s}v=5 m/s, what height hh does the ball strike the building?
Physics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:

The ball doesn't strike the building because it strikes the ground at d=1.62 meters.

Explanation:

V= 5 m/s < 70º

Vx= 1.71 m/s

Vy= 4.69 m/s

h= Vy * t - g * t²/2

clearing t for the flying time of the ball:

t= 0.95 s

d= Vx * t

d= 1.62 m

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when we touch a steel rod and a paper simultaneously we feel that the rod is comparatively colder .why?
Snezhnost [94]
It is so because the steel is more colder than our body.
4 0
3 years ago
If the equation on the board had shown 3 atoms of carbon on the reactants side, how many atoms of carbon would need to be repres
Sholpan [36]

3

Explanation:

If the equation on the board had shown 3 atoms of carbon on the reactants side, it would need 3 atoms of carbon on the product side to balance it.

This is in accordance to the law of conservation of mass which states that "matter is neither created nor destroyed during the course of chemical reaction, they are only transformed from one form to another".

We expect the same number of atoms on both sides of the equation. For example:

                    Fe + S  →   FeS

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Learn more:

Chemical equation brainly.com/question/2924195

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6 0
3 years ago
Read 2 more answers
What is the magnitude of a point charge that would create an electric field of 1.18 N/C at points 0.822 m away?
katrin [286]

Answer:

q = 8.85 x 10⁻¹¹ C

Explanation:

given,

Electric field, E = 1.18 N/C

distance, r = 0.822 m

Charge magnitude = ?

using formula of electric field.

E = \dfrac{kq}{r^2}

k is the coulomb constant

q= \dfrac{Er^2}{k}

q= \dfrac{1.18\times 0.822^2}{9\times 10^9}

  q = 8.85 x 10⁻¹¹ C

The magnitude of charge is equal to q = 8.85 x 10⁻¹¹ C

4 0
3 years ago
An electron is moving directly toward you in a horizontal path when it suddenly enters a uniform magnetic field that is either v
blagie [28]

Answer:

To your left

Explanation:

The direction of the force exerted on charged particle due to a magnetic field is given by the right-hand-rule, where:

- The index finger indicates the direction of motion of the electron

- the middle finger gives the direction of the magnetic field

- the thumb gives the direction of the force if the particle is positively charged - otherwise, the direction is reversed

in this case, we have an electron (so, a negatively charged particle):

- The direction of motion (index finger) is horizontal, toward you

- The electron begins to curve upward as it enters the field, so this means that the force exerted on the electrons is upward --> the thumb must point downward (because the electron is negatively charged)

- The index finger gives us the direction of the magnetic field: therefore, to your left.

3 0
4 years ago
If the atomic radius of Copper is 0.128 nm, calculate the volume of its unit cell in cubic nanometers. Round off the answer to t
hodyreva [135]

Explanation:

Below is an attachment containing the solution.

4 0
4 years ago
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