C......…..……...............
Answer:
7.22 x 10²³molecules
Explanation:
Given parameters:
Number of moles of hydrogen = 1.2moles
Unknown:
Number of molecules of hydrogen = ?
Solution:
From the concept of moles, a mole of a substance contains the Avogadro's number of particles.
1 mole of a substance = 6.02 x 10²³ molecules;
So; 1.2 moles of hydrogen = 1.2 x 6.02 x 10²³ molecules;
= 7.22 x 10²³molecules
Answer:
Frequency = 3.16 ×10¹⁴ Hz
λ = 0.95×10² nm
Explanation:
Energy associated with nth state is,
En = -13.6/n²
For n = 1
E₁ = -13.6 / 1²
E₁ = -13.6/1
E₁ = -13.6 ev
Kinetic energy of electron = -E₁ = 13.6 ev
For n = 5
E₅ = -13.6 / 5²
E₅ = -13.6/25
E₅ = -0.544 ev
Kinetic energy of electron = -E₅ = 0.544 ev
Wavelength of radiation emitted:
E = hc/λ = E₅ - E₁
hc/λ = E₅ - E₁
by putting values,
6.63×10⁻³⁴Js × 3×10⁸m/s / λ = -0.544ev - (-13.6 ev )
6.63×10⁻³⁴ Js× 3×10⁸m/s / λ = 13.056 ev
λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s /13.056 ev
λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s /13.056 × 1.6×10⁻¹⁹ J
λ = 19.89 ×10⁻²⁶ Jm / 13.056 × 1.6×10⁻¹⁹ J
λ = 19.89 ×10⁻²⁶ Jm / 20.9 ×10⁻¹⁹ J
λ = 0.95×10⁻⁷ m
m to nm:
0.95×10⁻⁷ m
×10⁹nm/1 m
0.95×10² nm
Frequency:
Frequency = speed of electron / wavelength
by putting values,
Frequency = 3×10⁸m/s /0.95×10⁻⁷ m
Frequency = 3.16 ×10¹⁴ s⁻¹
s⁻¹ = Hz
Frequency = 3.16 ×10¹⁴ Hz
The examination of a microscopic slice of an object with a petrological microscope in order to determine the source of the material, is known as thin-section analysis.
<h3>
What is thin section analysis?</h3>
The microscopic analysis of the content and structure of sediments is known as micromorphology, often known as thin-section analysis. Concepts of plasmic fabric and morphological traits and structures, which date from the early 1960s, were initially established in soil science.
<h3>
What makes petrography significant?</h3>
An essential tool for the fluid inclusion study is petrography. The fundamental purpose of petrography is to classify the fluid phases, such as monophase, biphase, or multiphase, and to deduce the relative chronology of the entrapment of fluid inclusions to determine whether it is primary, secondary, or pseudosecondary.
Learn more about the microscope with the help of the given link:
brainly.com/question/18661784
#SPJ4
Answer : The mass of chlorine reacted with the phosphorus is, 53.25 grams.
Explanation :
First we have to calculate the moles of phosphorus.
Now we have to calculate the moles of 
The balanced chemical reaction is:
From the balanced chemical reaction, we conclude that
As, 2 moles of phosphorous react with 3 moles of
So, 0.5 moles of phosphorous react with 
moles of
Now we have to calculate the mass of
Molar mass of = 71 g/mol
Therefore, the mass of chlorine reacted with the phosphorus is, 53.25 grams.
