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Novosadov [1.4K]
2 years ago
15

A roller coaster has the most ____ energy at the top of a hill and the most ____ energy at the bottom.

Physics
2 answers:
scoray [572]2 years ago
7 0

A is the correct answer

ki77a [65]2 years ago
7 0

A is the correct answe

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A 5kg bag falls a verticle height of 10m before hitting the ground.
g100num [7]

Answer:

u = 7m {s}^{ - 1}

Explanation:

We know that when we don't have air friction on a free fall the mechanical energy (I will symbololize it with ME) is equal everywhere. So we have:

me(1) = me(2)

where me(1) is mechanical energy while on h=10m

and me(2) is mechanical energy while on the ground

Ek(1) + DynamicE(1) = Ek(2) + DynamicE(2)

Ek(1) is equal to zero since an object that has reached its max height has a speed equal to zero.

DynamicE(2) is equal to zero since it's touching the ground

Using that info we have

m \times g \times h   =   \frac{1}{2}  \times m \times u {}^{2} \\

we divide both sides of the equation with mass to make the math easier.

9.8 \times 10 =  \frac{1}{2}  \times u {}^{2}  \\  \frac{98}{2}  = u {}^{2}  \\ u { }^{2} = 49 \\ u = 7

7 0
3 years ago
A device that converts mechanical energy into electricity is a
IgorLugansk [536]

Answer:

An electric generator is a device that converts a form of energy into electricity.

Explanation:

7 0
3 years ago
1. During which phase of the moon may a solar eclipse occur? (Points : 1)
kotykmax [81]
1. New moon
This is because the moon comes between the Earth and sun and this is only possible during its new moon phase.

2. Full moon
This is because the Earth comes between the Moon and the sun and the effect is only visible when there is a full moon.

3. Corona
The corona is the outer layer and is the only one visible when there is an eclipse.
7 0
3 years ago
Read 2 more answers
A ball with a volume of 3 cm3 and a density of 9.0 g/cm3 increases its velocity from 2 m/s to 6 m/s over a 12
V125BC [204]

Answer:

M = ρ V = 9 gm/cm^ 3 * cm^3 = 27 gm

a = (V2 - V1) / t = (6 - 2) m/s / 12 s = 1/3 m/s^2     the acceleration

F = M a = 27 gm * 1/3 m/s^2 = 9 dynes      net force applied

4 0
2 years ago
When applying a horizontal force of 30N, an object of mass 6 kg accelerates at 4m/s2. The force of friction on the surface must
Rus_ich [418]
Using Newton's Second Law, F = ma, where F is the net force

So the net force is:

F = (6kg)(4m/s^2) = 24N

Since you are applying a horizontal force of 30N, we can find the force of friction by the difference of the net force and the applied force.

30N-24N = 6N

F_{f} = 6N
4 0
2 years ago
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