Answer:
A. 1.19 * 10^(-13) N
B. 7.12 * 10^(15) m/s²
Explanation:
Parameters given:
Speed, v = 5.05 * 10^6 m/s
Angle, A = 64°
Magnetic field strength, B = 0.160T
Mass of proton, m = 1.673 * 10^(-27) kg
Charge of proton, q = 1.6023 * 10^(-19) C
A. Magnetic force is given as:
F = q*v*B*sinA
F = 1.6023 * 10^(-19) * 5.05 * 10^6 * 0.160 * sin64
F = 1.19 * 10^(-13) N
B. Force is generally given as:
F = m*a
Hence, we can find acceleration, a, by making it the subject of formula:
a = F/m
a = (1.19 * 10^(-13))/(1.673 * 10^-27)
a = 7.12 * 10^15 m/s²
<span>Free electrons may be transferred between bodies by "Contact Action"
When positively charged body comes close to a negatively charged body, then electron flows from positively to negatively charged body
In short, Your Answer would be Option B
Hope this helps!</span>
So as you may know atoms are neutral because the number of protons (+ charge) and the number of electrons( - charge) are the same so they cancel out. When a valence electron leaves an atom it will have a +1 charge because there is one less negative than positives or there is one more positive than negatives since a negative electron left. If a valence electron is added a -1 charge because there is now one more negative than positive!!!
hope that helps!!
