Answer:
E) rate of appearance of C = 0.45 M/s
rate of the reaction = 0.15 M/s
Explanation:
2A + B → 3C
Writing rate law for the reaction:
<u>Rate of reaction</u> = -
![\frac{d[A]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BA%5D%7D%7Bdt%7D)
= -![\frac{d[B]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BB%5D%7D%7Bdt%7D)
= 
![\frac{d[C]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BC%5D%7D%7Bdt%7D)
→ equation 1
Given that the rate of disappearance of A is 0.3 M/s
⇒ - = 0.3 M/s
⇒Rate of reaction = - = ×0.3 M/s
⇒<u>Rate of reaction = 0.15 M/s</u>
From equation 1, = - 
= ×0.3 M/s
⇒ = 0.45 M/s
or <u>the rate of appearance of C = 0.45 M/s</u>
I’m going to say Gravity.
Answer: 3.01 x 10^24 atoms
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 atoms
So, 1 mole of SI = 6.02 x 10^23 atoms
5.0 moles = Z atoms
To get the value of Z, cross multiply:
(Z atoms x 1 mole) = (6.02 x 10^23 atoms x 5.0 moles)
Z atoms•1 mole = 30.1 x 10^23 atoms•moles
Divide both sides by 1 mole
Z atoms•1 mole / 1 mole = 30.1 x 10^23 atoms•moles / 1 mole
Z = 30.1 x 10^23 atoms
[Place Z in standard form
So, Z = 3.01 x 10^24 atoms]
Thus, there are 3.01 x 10^24 atoms in 5.0 moles in SI
B.) Index of refraction of the second medium is higher
