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2 years ago

How far apart are a proton and electron if they exert an attractive force of 3n on one another

Physics

1 answer:

valina [46]2 years ago

3 0

Answer:

$distance=8.76\times 10^{-5}angstrom$

Explanation:

The 3N force must be attributed to electrostatic attraction between both charges.

The formula is known as Coulomb's law:

$F_E=k\times \dfrac{q_1\cdot q_2}{d^2}$

Where:

$F_E$ is the elecrostatic force: 3 N
k is the constant for Coulomb's law ≈ 9.00 × 10⁹ N . m² / C²
d is the distance that separate the centers of the charges
$q_1\text{ and }q_2$ are the values of the charges: ≈ ± 1.6 × 10⁻¹⁹ C

When you are not interested in the direction of the electrostatic force you just use the magnitudes of the charges.

Substitute in the formula and solve for d:

$3N=9.00\times 10^9N\cdotm^2/C^2\times\dfrac{(1.6\cdot 10^{-19}C)^2}{d^2}$

$d=8.76\times 10^{-15}m^2$

That can be converted to angstroms with the conversion factor:

1m = 10¹⁰ angstrom

$d= 8.76\times 10^{-15}m\times 10^{10}angstrom/m=8.76\times 10^{-5}angstrom$

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1) The gravitational force between Ellen and the moon is $1.56\cdot 10^{-3} N$

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$F=G\frac{m_1 m_2}{r^2}$

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