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dangina [55]
2 years ago
6

How far apart are a proton and electron if they exert an attractive force of 3n on one another

Physics
1 answer:
valina [46]2 years ago
3 0

Answer:

     distance=8.76\times 10^{-5}angstrom

Explanation:

The <em>3N force </em>must be attributed to electrostatic attraction between both charges.

The formula is known as Coulomb's law:

    F_E=k\times \dfrac{q_1\cdot q_2}{d^2}

Where:

  • F_E is the elecrostatic force: 3 N
  • k is the constant  for Coulomb's law ≈ 9.00 × 10⁹ N . m² / C²
  • d is the distance that separate the centers of the charges
  • q_1\text{ and }q_2 are the values of the charges: ≈ ± 1.6 × 10⁻¹⁹ C

When you are not interested in the direction of the electrostatic force you just use the magnitudes of the charges.

Substitute in the formula and solve for d:

      3N=9.00\times 10^9N\cdotm^2/C^2\times\dfrac{(1.6\cdot 10^{-19}C)^2}{d^2}

      d=8.76\times 10^{-15}m^2

That can be converted to angstroms with the conversion factor:

  • 1m = 10¹⁰ angstrom

d= 8.76\times 10^{-15}m\times 10^{10}angstrom/m=8.76\times 10^{-5}angstrom

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