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lisov135 [29]
4 years ago
10

A substance can absorb heat energy by the process of

Physics
1 answer:
slavikrds [6]4 years ago
3 0

Answer:

conduction,convection,radiation

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Define kinetic energy and thermal energy. Describe what happens to each as the temperature of a substances increases.
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Answer:

Kinetic energy is the amount of energy a object has while it's in motion, and thermal energy is heat energy. In this case when the heat rises in substances for example a solid it will transform into a liquid causing the molecules to move faster which is a increase of kinetic energy.

Explanation:

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If you repeat an experiment and the results are very different from the results you got the first time, the next step would be t
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Redo the previous experiments.

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A 77-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.
jekas [21]

Answer:

Explanation:

From the question, we can see that the elevator is at a constant speed, invariably, acceleration is zero. And thus, there is no external force acting in the man, asides from force of gravitation acting on the man between those 5s. Now, we solve the question using newton's second law of motion.

The second law of motion states that, "the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object."

Summation Fy = ma(y)

F(n) - F(g) = 0

F(n) - mg = 0

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You have a 1.8m long copper wire. You want to make an N-turn current loop that generates a 2.0mT magnetic field at the center wh
NikAS [45]

Answer:

The diameter is  0.022m.

Explanation:

The magnetic field B at the center of the coil is given by

(1). B = \dfrac{\mu_0 NI}{d}

where \mu_0 = 1.26*10^{-6} m\:kg\:s^{-2} A^{-2} is the magnetic constant, I is the current, N number of coils, and d is the diameter of the coil.

Now, if we call L the length of the wire, then it must be true that

\pi dN = L <em>(this says </em>N<em> coil circumferences (</em>c=\pi d<em>) fit into </em>L<em> )</em>

\therefore N = \dfrac{L}{\pi d }

putting this into equation (1) we get:

B = \dfrac{\mu_0 IL }{\pi d^2}

solve for d:

\boxed{d = \sqrt{\dfrac{\mu_0I L }{\pi B} }}

putting in the numerical values

\mu_0 = 1.26*10^{-6} m\:kg\:s^{-2} A^{-2}

I =1.3A

L= 1.8m

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we get:

d = \sqrt{\dfrac{(1.26*10^{-6})(1.3) *1.8 }{\pi (2.0*10^{-3})} }

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