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Alecsey [184]
3 years ago
15

What is the difference between static friction and kinetic friction

Physics
2 answers:
alekssr [168]3 years ago
6 0
Static friction keeps stationary objects calm
Kinetic friction slows down a moving thing
sergejj [24]3 years ago
3 0
The Force of Static Friction<span> keeps a stationary object at rest! Once the Force of</span>Static Friction<span> is overcome, the Force of </span>Kinetic Friction<span> is what slows down a moving object.</span>
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A wrench 20 cm long lies along the positive y-axis and grips a bolt at the origin. A force is applied in the direction 0, 4, −3
Andreyy89

Answer:

1250 N

Explanation:

length of wrench = 20 cm = 0.2 m

Write the length of wrench in vector form

r = 0.2 j metre

Direction of force= \frac{0i+4j-3k}{\sqrt{0 + 16 + 9}}=\frac{0i+4j-3k}{5}

Let the magnitude of force is F

So, write the force in vector form

F = F  \frac{0i+4j-3k}{\sqrt{0 + 16 + 9}}=\frac{0i+4j-3k}{5}

torque, T = 150 Nm

Torque = T = r x F

150 i =0.2j\times F\frac{0i+4j-3k}{5}

F = 1250 N

Thus, the magnitude of force is 1250 N.

6 0
3 years ago
Which statement best describes the difference between acceleration and velocity?
kramer

Answer:

C

Explanation:

acceleration is a change in velocity which means a time rate change in velocity but velocity is the time rate change in displacement

6 0
3 years ago
Please help me answer this question I will be given the brainliest as well
Sophie [7]

draw a horizontal straight line from 25 to 75 and connects the line drawn at 75 to the bottom of the graph (0) at 90 with a straight line

3 0
3 years ago
A small model car with mass m travels at a constant speed on the inside of a track that is a vertical circle radius 5.00 m. If t
dolphi86 [110]
One point to another
6 0
3 years ago
Three forces act on a moving object. One force has a magnitude of 83.7 N and is directed due north. Another has a magnitude of 5
LekaFEV [45]

Answer:

  • |\vec{F}_3| = 102.92 \ N
  • \theta = 57 \° 24 ' 48''

Explanation:

For an object to move with constant velocity, the acceleration of the object must be zero:

\vec{a} = \vec{0}.

As the net force equals acceleration multiplied by mass , this must mean:

\vec{F}_{net} = m \vec{a} = m * \vec{0} = \vec{0}.

So, the sum of the three forces must be zero:

\vec{F}_1 + \vec{F}_2 + \vec{F}_3 = \vec{0},

this implies:

\vec{F}_3  = - \vec{F}_1 - \vec{F}_2.

To obtain this sum, its easier to work in Cartesian representation.

First we need to define an Frame of reference. Lets put the x axis unit vector \hat{i} pointing east,  with the y axis unit vector \hat{j} pointing south, so the positive angle is south of east. For this, we got for the first force:

\vec{F}_1 = 83.7 \ N \ (-\hat{j}),

as is pointing north, and for the second force:

\vec{F}_2 = 59.9 \ N \ (-\hat{i}),

as is pointing west.

Now, our third force will be:

\vec{F}_3  = - 83.7 \ N \ (-\hat{j}) - 59.9 \ N \ (-\hat{i})

\vec{F}_3  =  83.7 \ N \ \hat{j}  + 59.9 \ N \ \hat{i}

\vec{F}_3  =  (59.9 \ N , 83.7 \ N )

But, we need the magnitude and the direction.

To find the magnitude, we can use the Pythagorean theorem.

|\vec{R}| = \sqrt{R_x^2 + R_y^2}

|\vec{F}_3| = \sqrt{(59.9 \ N)^2 + (83.7 \ N)^2}

|\vec{F}_3| = 102.92 \ N

this is the magnitude.

To find the direction, we can use:

\theta = arctan(\frac{F_{3_y}}{F_{3_x}})

\theta = arctan(\frac{83.7 \ N }{ 59.9 \ N })

\theta = 57 \° 24 ' 48''

and this is the angle south of east.

7 0
3 years ago
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