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Alecsey [184]
3 years ago
15

What is the difference between static friction and kinetic friction

Physics
2 answers:
alekssr [168]3 years ago
6 0
Static friction keeps stationary objects calm
Kinetic friction slows down a moving thing
sergejj [24]3 years ago
3 0
The Force of Static Friction<span> keeps a stationary object at rest! Once the Force of</span>Static Friction<span> is overcome, the Force of </span>Kinetic Friction<span> is what slows down a moving object.</span>
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Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 30.0 mph and half the
salantis [7]

Answer:

Explanation:

Given

Distance to grandmother's house=100 mi

it is given that during return trip Julie spend equal time driving with speed 30 mph and 70 mph

Let Julie travel x mi with 30 mph and 100-x with 70 mph

\frac{x}{30}=\frac{100-x}{70}

x=30 mi

Therefore

Julie's Average speed on the way to Grandmother's house=\frac{100}{\frac{50}{30}+\frac{50}{70}}

=42 mph

On return trip

=\frac{100}{2\frac{30}{30}}=50 mph

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Answer:

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Explanation:

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Similar to what you see in your textbook, you can generally omit the multiplication symbol as you answer questions online, excep
lidiya [134]

Answer:

ma= ma

m⋅a = m⋅a

And equivalently:

am=ma

a⋅m = m⋅a

Explanation:

Question

Assuming this question "Similar to what you see in your textbook, you can generally omit the multiplication symbol as you answer questions online, except when the symbol is  needed to make your meaning clear. For example, 1*10^5 is not the same as 110^5 . When you need to be explicit, type * (Shift + 8) to insert the multiplication operator. You will see a multiplication dot (⋅) appear in the answer box. Do not use the symbol x. For example, for the expression ma,

typing m⋅a would be correct, but mxa would be incorrect".

Solution to the problem

For this case we want to write a expression for ma, and based on the previous info we can write:

ma= ma

m⋅a = m⋅a

And equivalently:

am=ma

a⋅m = m⋅a

But is not correct do this:

mxa=mxa

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