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WARRIOR [948]
3 years ago
11

PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE ANSWERRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR

RRRRR

Chemistry
2 answers:
jeyben [28]3 years ago
6 0

This would be a Neap tide.

A tide just after the first or third quarters of the moon when there is the least difference between high and low water.

Oksanka [162]3 years ago
5 0

The answer is a neap tide. Neap tides occur after a 1st and 3rd quarter moon. Spring tides occur after a new or full moon. The answer is A... Neap

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Which subatomic particles are located in the nucleus of a ca-40 atom?
san4es73 [151]

Answer:

3) neutrons and protons

Explanation:

I just completed Grade 11 Chemistry with a 97% and I'm still under the impression that all atoms have only neutrons and protons in their nuclui.

I apologize if this is a question above my current education.

3 0
3 years ago
Determine the number of significant in 400
Leya [2.2K]

Answer:

400 or 4x102 indicates only onesignificant figure. (To indicate that the trailing zeros are significant a decimal point must be added. 400. has threesignificant digits and is written as 4.00x102 in scientific notation.) Exact numbers have an infinite number of significant digits but they are generally not reported.

6 0
3 years ago
A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s
Talja [164]

<u>Answer:</u> The enthalpy of the reaction is -4134.3 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of calorimeter = 1.900 kg = 1900 g  (Conversion factor:  1 kg = 1000 g)

c = heat capacity of calorimeter = 3.21 J/g.K

\Delta T = change in temperature = 4.542 K

Putting values in above equation, we get:

q=1900g\times 3.21J/g.K\times 4.542K=27701.66J=27.7kJ

Heat released by the calorimeter will be equal to the heat absorbed by the reaction.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of hexane = 0.580 g

Molar mass of hexane = 86.18 g/mol

Putting values in above equation, we get:

\text{Moles of hexane}=\frac{0.580g}{86.18g/mol}=0.0067mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = -27.7 kJ

n = number of moles of hexane= 0.0067 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{-27.7kJ}{0.0067mol}=-4134.3kJ/mol

Hence, the enthalpy of the reaction is -4134.3 kJ/mol

5 0
3 years ago
Write a balanced chemical equation for the reaction of solid potassium with liquid water. express your answer as a chemical equa
murzikaleks [220]
In writing chemical reactions, it is important that you know the chemical formula of each substance and in balancing them, it should be that the number of each element in both side are equal. 

2K(s) + 2H2O(l) = 2KOH(aq) + H2(g)

4 0
3 years ago
Read 2 more answers
What is the concentration in mol L-l of a 12% solution of tetrahydrate magnesium chloride (MgCl2)?
madreJ [45]

The concentration in mol L-l (M) = 0.717

<h3>Further explanation</h3>

Given

12% solution of tetrahydrate magnesium chloride (MgCl₂)

Required

The concentration

Solution

Tetrahydrate magnesium chloride (MgCl₂)⇒MgCl₂.4H₂O

MW = Ar Mg+2. Ar Cl+8. Ar H + 4. Ar O

MW=24.31 + 2 x 35.45 + 8 x 1.01 + 4 x 16

MW=24.31+70.9+8.08+64

MW=167.29 g/mol

12% solution = 12 % m/v = 12 g in 100 ml solution

For 1 L solution :

\tt \dfrac{1}{0.1}\times 12~g=120~g

The concentration in g/L = 120 g/L

Convert grams to moles :

\tt mol=\dfrac{120}{167.29}=0.717

3 0
3 years ago
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