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2 years ago

PLEASE HELP 20 points

Chemistry

1 answer:

777dan777 [17]2 years ago

4 0

n = 1.5atm (15L) / .0821 (280k) = .98 mol NaCl

NaCl = 22.99g Na + 35.45g Cl = 58.44g NaCl

58.44g NaCl x .98 mol NaCl = 57.27g NaCl

Explanation:

hope you get it right :)

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Step 1: Data given

Mass of the sample = 5.54 grams

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Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles NaOH

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Step 5: Calculate mass CH3COOH

Mass CH3COOH = moles CH3COOH * molar mass CH3COOH

Mass CH3COOH = 0.00301 moles * 60.05 g/mol

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Mass % = 3.26 %

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