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Kryger [21]
4 years ago
8

Why would it be hard to find the average CO2 level if the light intensity were low

Chemistry
1 answer:
kondor19780726 [428]4 years ago
5 0
Computers can't really detect such a low intensity.......?, I hope I'm right.
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46. Which of the following is not a form of matter?
Mice21 [21]
C cuz it just doesn’t make sense
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3 years ago
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imagine that you're able to fully dissolve a powered substance and water what can be said about this creation
Softa [21]
We can say that the water is the solvent, and the powder is the solute. This is also a solution altogether. 

Explanation:- A solute is the thing being dissolved into the solvent. While the solvent is what when the solute is being dissolved in. Together, they make a solution. 
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3 years ago
What volume of 0.200 M H2SO* will be needed to neutralize<br><br> 50.00 mL of 0.178 MNaOH?
mixas84 [53]

Answer:

10.00 mL

Explanation:

Please, do not forget to write the dot and 2 of Zeros after the number 10 in the answer!

Please see the step-by-step solution in the picture attached below.

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7 0
4 years ago
BRAINLIEST IF CORRECT
zhannawk [14.2K]

Answer:

1 a person sings into a microphone

2 the sound is converted into an electrical signal

3 the analog signal is converted into a digital signal made of many samples of the digital sound

4 the samples of the sound is converted into 1s and 0s

5 the digital pattern is converted to a medium such as a hard disk or flash drive

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5 0
3 years ago
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What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?
yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃  +  3C  →  4Fe  +  3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5  . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83  . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

5 0
3 years ago
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