Answer:
Option d is correct option = Frequency of light is 6.56×10⁻² Hz
Explanation:
Given data:
Frequency of light = ?
wavelength of light = 4.57×10⁹m
Solution:
Formula:
Speed of light = wavelength × frequency
c = λ × f
f = c/λ
This formula shows that both are inversely related to each other.
The speed of light is 3×10⁸ m/s
Frequency is taken in Hz.
It is the number of oscillations, wave of light make in one second.
Wavelength is designated as "λ" and it is the measured in meter. It is the distance between the two crust of two trough.
Now we will put the values in formula.
f = 3×10⁸ m/s / 4.57×10⁹m
f = 0.656×10⁻¹s⁻¹
s⁻¹ = Hz
f = 0.656×10⁻¹ Hz or 6.56×10⁻² Hz
Answer:
10.3 g Al
Explanation:
To find the excess mass of Al, you need to (1) convert grams I₂ to moles I₂ (via molar mass), then (2) convert moles I₂ to moles AlI₃ (via mole-to-mole ratio from equation coefficients), then (3) convert moles AlI₃ to grams AlI₃ (via molar mass). Now that you have the actual amount of AlI₃ produced, you need to (4) convert grams AlI₃ to moles AlI₃ (via molar mass), then (5) convert moles AlI₃ to moles Al (via mole-to-mole ratio from equation coefficients), and then (6) convert moles Al to grams Al (via molar mass). Now that you know the amount of Al actually needed to produce the product, you need to (7) find the excess mass of Al.
Molar Mass (Al): 26.982 g/mol
Molar Mass (I₂): 2(126.90 g/mol)
Molar Mass (I₂): 253.8 g/mol
Molar Mass (AlI₃): 26.982 g/mol + 3(126.90 g/mol)
Molar Mass (AlI₃): 407.682 g/mol
2 Al(s) + 3 I₂(g) -------> 2 AlI₃(g)
113 g I₂ 1 mole 2 moles AlI₃ 407.682 g
------------- x ---------------- x ---------------------- x ------------------- = 121 g AlI₃
253.8 g 3 moles I₂ 1 mole
121 g AlI₃ 1 mole 2 moles Al 26.982 g
--------------- x ------------------ x --------------------- x ----------------- = 8.01 g Al
407.682 g 2 moles AlI₃ 1 mole
Starting Amount - Mass Needed = Excess
18.3 g Al - 8.01 g Al = 10.3 g Al
Answer:
i cant under stand what you are trying to say
Explanation:
Inherited it from his grandfather
Answer:
P = 20atm
Explanation:
P1 = 10atm
T1 = 10K
P2 = ?
T2 = 20K
This question requires the use of pressure law which states that the pressure of a fixed mass of gas is directly proportional to its temperature provided its volume remains constant
Mathematically,
P = kT, k = P / T
P1 / T1 = P2 / T2 = P3 / T3=........=Pn / Tn
P1 / T1 = P2 / T2
P2 = (P1 × T2) / T1
P2 = (10 × 20) / 10
P2 = 20atm
The final pressure of the gas is 20atm