Ask question

Ask question

All categories

3 years ago

10

Methane gas at 25°C, 1 atm enters a reactor operating at steady-state and burns with 80% theoretical air entering at 227°C, 1 at

m. An equilibrium mixture of CO2, CO, H2O(g), H2, and N2 exits at 1427°C, 1 atm. Assume N2 is inert.
Determine, per kmol of methane entering;
(a) the composition of the exiting mixture.
(b) the heat transfer between the reactor and its surroundings, in kJ.
Neglect kinetic and potential energy effects.

1 answer:

Damm [24]3 years ago

5 0

Answer:

The composition of existing misture are,

a.

Co2 =0.5679

Co= 0.9326

H2O=1.6326

H2 = 0.3679

N2 = 0.6016

b.

K= 3.3878

Explanation:

Please see attachment for the solving.

You might be interested in

A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.15 m2 and whose thickn

Oxana [17]

Answer:

The percentage loss of the window is $E = 97.3$ %

Explanation:

From the question we are told that

The area of pane of glass is $A = 0.15 m^2$

The thickness is $d = 5mm = \frac{5}{1000} = 0.005m$

The thickness of the wall is $D = 0.15m$

The area of the wall is $a = 10m^2$

Generally the heat lost as a result of conduction of the window is

$Q_{window} = \frac{j_{glass} * A * (\Delta T) }{d}$

Where $j_{glass}$ is the thermal conductivity of glass which has a constant value of

$j_{glass} = 0.80 J/(s \cdot m \cdot C^o)$

Substituting values

$Q_{window} = \frac{ 0.80 * 0.15 * (\Delta T) }{0.005}$

$Q_{window} = 24 \Delta T$

Generally the heat lost as a result of conduction of the wall is

$Q_{wall} = \frac{j_{styrofoam} * A * (\Delta T) }{d}$

$j_{styrofoam}$ s the thermal conductivity of Styrofoam which has a constant value of $j_{styrofoam} = 0.010J / (s \cdot m \cdot C^o)$

Substituting values

$Q_{wall} = \frac{ 0.010 * 10 * (\Delta T) }{0.15}$

$Q_{wall} = 0.667 \ \Delta T$

Now the net loss of heat is

$Q_{net} = Q_{window} + Q_{wall}$

Substituting values

$Q_{net} = 24 + 0.667$

$Q_{net} = 24.667$

Now the percentage loss by the window is

$E = \frac{Q_{window} }{Q_{net}} * 100$

Substituting value

$E = \frac{24}{24 .667} * 100$

$E = 97.3$ %

4 0

4 years ago

Puan puan puan vericim

masha68 [24]

Give me those points

4 0

3 years ago

Read 2 more answers

In the figure show, what's the distance from point H to point C?

padilas [110]

Answer:

B.

Explanation:

I think not sure hehe

4 0

3 years ago

Lets Try This: study the pictures. Describe what you see and think about it. write your answer on a sheet of paper. home room

Yuliya22 [10]

Answer: I see three children cleaning the lawn while one of them are raking the leaves and one is holding a dust pan. The other child is holding a bucket. On the other picture, i see a young boy watering plants.

BTW: these pictures are not very clear so answers may vary.

Explanation:

4 0

2 years ago

The type of current that flows from the electrode across the arc to the work is called what?

Scrat [10]

Answer:

Direct current.

Explanation:

5 0

3 years ago