Answer:
MRR = 1.984
Explanation:
Given that
Depth of cut ,d=0.105 in
Diameter D= 1 in
Speed V= 105 sfpm
feed f= 0.015 ipr
Now the metal removal rate given as
MRR= 12 f V d
d= depth of cut
V= Speed
f=Feed
MRR= Metal removal rate
By putting the values
MRR= 12 f V d
MRR = 12 x 0.015 x 105 x 0.105
MRR = 1.984
Therefore answer is -
1.944
Answer:
Test code:
>>u=10;
>>g=9.8;
>>q=100;
>>m0=100;
>>vstar=10;
>>tstar=fzero_rocket_example(u, g, q, m0, vstar)
Explanation:
See attached image
Answer:
a. SATA cable
Explanation:
A troubleshooting process could be as follows:
- <em>The Power supply</em> is working since it is possible to receive the <em>error message</em>.
- With no <em>OS available</em> is not possible to 'roll back the Windows update'.
Then, two alternatives remain:
- SATA cable.
- Hard drive.
In the reliability configuration of the components, <em>the hard drive depends on the SATA cable to work properly. </em>A faulty SATA cable would prevent the hard drive to work correctly. Then,<em> </em>a loosely SATA cable is the first thing to check before proceeding with the hard disk.
Additionally, a loosely SATA cable is also a common source of error messages like "OS not found" and it would be easier step to be discarded before continuing with a more demanding one like checking the hard drive.
Answer:
The percentage of silicon atoms per unit volume that are displaced in the single crystal lattice = 0.001 %
The percentage of silicon atoms per unit volume that are displaced in the single crystal lattice with boron atoms = 0.4 ×
%
Explanation:
No. of phosphorus atoms = 5 × 
The volume occupied by a single Si atom
2 × 
= 5 × 
Put the values in above equation we get
PCT = 
%
These are the percentage of silicon atoms per unit volume that are displaced in the single crystal lattice.
(b).
No. of boron atoms = 2 × 
The volume occupied by a single Si atom
2 ×
= 5 ×
Put the values in above equation we get
PCT = 0.4 × %
These are the percentage of silicon atoms per unit volume that are displaced in the single crystal lattice.
Answer:
length of cylinder can not calculated
Explanation:
given data
tensile stress = 10,000 psi
Original length = 1
Original cross-sectional area = 0.1 in²
Yield strength, σy = 9 ksi
Young’s modulus, E = 1000 ksi
solution
we can see that here that applied stress is greater than yield stress of material that is express
1000 ksi > 9 ksi
so here hooks law and strain relation is not working
so length of cylinder can not calculated
as stress applied 10000 psi
