Answer:
32.25
Explanation:
8NH3 + 3Cl2 → 6NH4Cl + N2
NH3 = 17 g/mol
number of moles = 1
NH4Cl= 43 g/mol
number of moles = 3/4
mass= 43 × ¾ ≈ 32.25 g
It is a good thing that you already have answered the first question. Now, moving on to the second question, there exist an equation for the neutralization of acid by a base that is shown below,
M₁V₁ = M₂V₂
Now, all the variables in the equation are given except for our unknown which is the V₂. Substituting the known values from the given above,
(0.1 M)(25 mL) = (0.05 M)(V₂)
The value of V₂ from the equation above is 50 mL. Therefore, 50 mL of 0.05 M NaOH solution will be needed to completely react with HNO3.
Mass of Aluminum = 157.5 g
<h3>Further explanation</h3>
Given
17.5 g of Hydrogen
Required
Mass of Aluminum
Solution
Reaction
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
mol Hydrogen :
= mass : molar mass
= 17.5 g : 2 g/mol
= 8.75
From the equation, mol Al :
= 2/3 x mol H₂
= 2/3 x 8.75
= 5.83
Mass Al :
= 5.83 x 27 g/mol
= 157.5 g
Out of the statements given, the correct statement about ribosomes that is correct is that Prokaryotic ribosomes are smaller than eukaryotic ribosomes. The correct answer is B.
