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azamat
3 years ago
10

Please Help!!! Motion

Physics
1 answer:
MAXImum [283]3 years ago
5 0

Answer:

The answer to your question is: c

Explanation:

a) The car stops moving.  The statement is true because fromthe interval 5 to 10 s, the car does not move.

b) The car changes direction. This statement is true because from 0 to 5 seconds, the vehicle is moving away from the origin and from 10 to 12.5 is getting closer to the origin.

c) The speed of the car is constant during the trip. This sentence is wrong because from 0 to 5 is moving with one velocity and from 10 to 12.5 is moving with a different velocity.

d) The car returns to the starting point of the trip. This sentence is correct, the movement starts at displacement equals to zero and ends at the same displacement.

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If a car is traveling forward at 15 m/s, how fast will it be going in 1.2 seconds if the acceleration is
Law Incorporation [45]

Answer:

3

Explanation:

v = v⁰ (its original speed) + a (negative acceleration) X t² (time)

v = 15 - 10 x 1.2 = 15 - 12 = 3 (it's slowing down)

3 0
2 years ago
a stone with a mass of 2.40 kg is moving with velocity (6.60î − 2.40ĵ) m/s. find the net work (in j) on the stone if its velocit
ch4aika [34]

By the work energy theorem, the total work done on the stone is given by its change in kinetic energy,

W = \Delta K = \dfrac m2 ({v_2}^2 - {v_1}^2)

We have

\vec v_1 = (6.60\,\vec\imath - 2.40\,\vec\jmath)\dfrac{\rm m}{\rm s} \implies {v_1}^2 = \|\vec v_1\|^2 = 49.32 \dfrac{\rm m^2}{\rm s^2}

\vec v_2 = (8.00\,\vec\imath + 4.00\,\vec\jmath) \dfrac{\rm m}{\rm s} \implies {v_2}^2 = \|\vec v_2\|^2 = 80.0\dfrac{\mathrm m^2}{\mathrm s^2}

Then the total work is

W = \dfrac{2.40\,\rm kg}2 \left(80.0\dfrac{\rm m^2}{\rm s^2} - 49.32\dfrac{\rm m^2}{\rm s^2}\right)  \approx \boxed{36.8\,\rm J}

5 0
2 years ago
A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N
mart [117]

Answer:

205N

Explanation:

The net force (F) is the difference between the applied force(F_{A}) and the kinetic frictional force(F_{R}). i.e

F = F_{A} - F_{R}    -----------------(i)

Note that;

F_{R} = μmg

Where;

μ = coefficient of kinetic friction

m = mass of the body

g = acceleration due to gravity = 10m/s²

Equation (i) then becomes;

F = F_{A} - μmg        -------------------(ii)

<em>Given from question;</em>

m = mass of motorcycle = 150kg

μ = 0.03

F_{A} = 250N

Substitute these values into equation (ii) as follows;

F = 250 - (0.03 x 150 x 10)

F = 250 - (45)

F = 205N

Therefore, the net force applied to the motorcycle is 205N

3 0
3 years ago
Which statement best describes how energy transfer within earths atmosphere 10 affect a weather condition? A)during radiation ob
Pie

Answer: D

Explanation: During convection, heat is being transferred between substances in direct contact with each other by electro magnetic waves.

Using the molten rock to explain the convection in the earth relative to how if affects the weather condition. Here, the rock is in a molten state, rising up from the bottom of the mantle after becoming hotter and less dense from the heat of the earth's core. As the rock loses heat into the earth's crust, it become cooler and more dense,sinking back to the core. These constantly circulating cells of hotter and cooler molten rock help to heat the earth's surface.

5 0
3 years ago
A rope pulls on a metal box at an angle of 60.0° with a force of 255 N. The box moves horizontally for 10.0 m. How much work was
N76 [4]

w = F•s•cos θ

= 255•10•cos 60°

= 255•10•½

= 1275 joule

7 0
3 years ago
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