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QveST [7]
3 years ago
14

A sprinter moving at 10 m/s slows down at a rate of 1.4 m/s2. how fast is the runner moving after 4 seconds?

Physics
2 answers:
Tema [17]3 years ago
6 0

Answer:

vf= 4.4 m/s

Explanation:

Kinematics

Because the sprinter moves with uniformly accelerated movement we apply the following formula:

vf= v₀+at Formula (1)

Where:  

t : time in seconds (s)

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration in m/s²

Data

t = 4 s

v₀ = 10 m/s

a = -1.4 m/s²

Problem development

We replace data in the formula (1) to calculate the speed of the sprinter in 4 seconds :

vf = 10-1.4(4)

vf= 4.4 m/s

AURORKA [14]3 years ago
3 0
V=u+at
v=10+(-1.4 (4))
=10-5.6
=4.4m/s
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A space station in the shape of a 100 m-diameter (50m radius) wheel is spinning so as to impart a linear tangential speed of 22.
zalisa [80]

Answer:

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Explanation:

given data

artificial gravity a1 = 1 g

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diameter = 100 m

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solution

As acceleration is  ∝ v²

so we can say

\frac{a2}{a1} = \frac{v2}{v1}    .....................1

put here value

\frac{2}{1} = \frac{v2}{22.1}  

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so correct option is b. 31.3 m/s

4 0
3 years ago
A shopping cart rolls from x=19.9m to x=5.40m with an average velocity of -0.418m/s. How much time did it take? (unit=s)
andrew11 [14]

Given

initial position = Xi= 19.9m

Final position Xf = 5.4m

Average velocity= Va = -0.418m/s

it shows displacement is reverse.

To find  t=?

As   Va = (Xf- Xi) / t

t = (Xf-Xi) / ( Va)

t = ( 5.4-19.9) / (-0.418)

t = (-14.5 ) / (-0.418)   (-ve sign cancel out at numerator and denominator)

t =34.69 s

8 0
3 years ago
A 450g mass on a spring is oscillating at 1.2Hz. The totalenergy of the oscillation is 0.51J. What is the amplitude.
Volgvan

Answer:

A=0.199

Explanation:

We are given that  

Mass of spring=m=450 g==\frac{450}{1000}=0.45 kg

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Frequency of oscillation=\nu=1.2Hz

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We have to find the amplitude of oscillations.

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Where \omega=2\pi\nu=Angular frequency

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A^2=\frac{2\times 0.51}{0.45\times (2\times \frac{22}{7}\times 1.2)^2}=0.0398

A=\sqrt{0.0398}=0.199

Hence, the amplitude of oscillation=A=0.199

4 0
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When a metal reacts with a non-metal it forms what???​
Snezhnost [94]

Answer:

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5 0
3 years ago
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