Which fact is true during a fission chain reaction?

Juli2301 [7.4K]

AC reverses the current in periods, and the current flows in 2 directions.
DC only flows in one direction and is constant.

AC is typically used to transfer power over long distances from a generator to your home, stepping it up after it's generated to send it over the distance, then stepping it back down so that it is usable in your home.

DC is used typically inside of devices, as it sends a certain amount of electricity through the wires.

Nicolas Tesla, was ripped off by Edison to replace his DC stations with AC instead. ^^

4 0

3 years ago

an object has a constant acceleration of 3.2 m/s^2.at a certain instant its velocity is 10 m/s . what is its velocity after 5 se

aleksandrvk [35]

So here, you're looking for distance. The formula is D=vt+1/2at^2.

Lets plug in the informations.

10 m/s is our v (initial velocity)

5 second is out t(time)

3.2 m/s is our a(acceleration)

10m/s(5)+1/2(3.2m/s+5^2)

50m/s+1/2(28.2)

50m/s+14.1

Answer =64.1 m

Glad to help you out buddy. Let me know if you need help.

5 0

3 years ago

You’re still in a redecorating mood and want to move a 35kg bookcase to a different place in the living room. You exert 58 N on

CaHeK987 [17]

Answer: 0.16

Explanation:

Newton's second law states that the resultant of the forces exerted on the bookcase is equal to the product between the mass (m) and the acceleration (a):

$F-F_f = ma$

where

F = 58 N is the force applied

Ff is the frictional force

Substituting, we find the frictional force

$F_f = F-ma=58 N-(35 kg)(0.12 m/s^2)=53.8 N$

The frictional force has the form:

$F_f = \mu mg$

where $\mu$ is the coefficient of kinetic friction. Re-arranging the formula, we can find the coefficient:

$\mu=\frac{F_f}{mg}=\frac{53.8 N}{(35 kg)(9.8 m/s^2)}=0.16$

4 0

4 years ago

A velocity selector has a magnetic field of magnitude 0.22 T perpendicular to an electric field of magnitude 0.51 MV/m.

ohaa [14]

Answer:

speed of a particle = 2.31 × $10^{6}$ m/s

energy of proton required = 27.77 KeV

energy of electron required = 15.171 eV

Explanation:

given data

magnetic field of magnitude = 0.22 T

electric field of magnitude = 0.51 MV/m

to find out

speed of a particle and energy must protons have to pass through undeflected and energy must electrons have to pass through undeflected

solution

we know that force due to magnetic and electric field is express as

force due to magnetic field B = qvB ..............1

and force due to electric field E = qE .....................2

so without deflection force due to magnetic field = force due to electric field

so here qvB = qE

and V = $\frac{E}{B}$ ...................3

put here value

V = $\frac{0.51*10^6}{0.22}$

speed of a particle = 2.31 × $10^{6}$ m/s

and

now energy of proton required will be here as

energy of proton required = mass of proton × $\frac{V^2}{2}$

put here value

energy of proton required = 1.67 × $10^{-27}$ × $\frac{(2.31*10^6)^2}{2}$

energy of proton required = 4.45 × $10^{-15}$ J

energy of proton required = 4.45 × $10^{-15}$ J ÷ (1.602 × $10^{-19}$

energy of proton required = 27777.777 eV

energy of proton required = 27.77 KeV

and

now we get here energy of electron required that is

energy of electron required = mass of electron × $\frac{V^2}{2}$

put here value

energy of electron required = 9.11 × $10^{-31}$ × $\frac{(2.31*10^6)^2}{2}$

energy of electron required = 24.305× $10^{-19}$ J

energy of electron required = 24.305 × $10^{-19}$ J ÷ (1.602 × $10^{-19}$

energy of electron required = 15.171 eV

5 0

4 years ago

Read 2 more answers

The energy needed to change an amount of a substance from a solid to a liquid is the

Korvikt [17]

Answer:

Heat or thermal energy!!!

Explanation: When heat is added the particles speed up at rapid rates causing the state of the object to change nd in order to melt it must be heated.

3 0

4 years ago