Answer : The fugacity in the solution is, 16 bar.
Explanation : Given,
Fugacity of a pure component = 40 bar
Mole fraction of component = 0.4
Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.
Now we have to calculate the fugacity in the solution.
Formula used :
where,
= fugacity in the solution
= fugacity of a pure component
= mole fraction of component
Now put all the give values in the above formula, we get:
Therefore, the fugacity in the solution is, 16 bar.
To determine the velocity of an object, you need to know the displacement and the change in time.
v = displacement / change in time
The answer for the following problem is described below.
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Explanation:
Given:
enthalpy of combustion of glucose(Δ
of 
) =-1275.0
enthalpy of combustion of oxygen(Δ of 
) = zero
enthalpy of combustion of carbon dioxide(Δ of 
) = -393.5
enthalpy of combustion of water(Δ of 
) = -285.8
To solve :
standard enthalpy of combustion
We know;
Δ = ∈Δ (products) - ∈Δ (reactants)
(s) +6 (g) → 6 (g)+ 6 (l)
Δ = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]
Δ = [6 (-393.5) + 6(-285.8)] - [0 - 1275]
Δ = 6 (-393.5) + 6(-285.8) - 0 + 1275
Δ = -2361 - 1714 - 0 + 1275
Δ =-2800 kJ
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Answer:
4.1 moles of FeCl₃
Explanation:
The reaction expression is given as shown below:
2Fe + 3Cl₂ → 2FeCl₃
Number of moles of Cl₂ = 6.1moles
So;
We know that from the balanced reaction expression:
3 moles of Cl₂ will produce 2 moles of FeCl₃
Therefore 6.1moles of Cl₂ will produce 
= 4.1 moles of FeCl₃
The number of moles is 4.1 moles of FeCl₃
