Answer: 1.86 m
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

where,
n = moles of solute
= weight of solvent in g
Given : 15.0 grams of
is present in 100 g of solution
Moles of solute 
mass of solution = 100 g
density of solution = 1.127g/ml
mass of solvent = mass of solution - mass of solute = 100 g - 15.0g = 85.0 g

Thus molality of a 15.0% by mass solution of
is 1.86m.
Answer:
Explanation:
48000 minutes [ 1 hour / 60 min ] 1 day / 24 hours ] [365 days / year]
48000 * [ 1/(60 * 24 * 365)]
48000 * [1 / 525600]
There are 0.0930954years in 48000 minutes
Answer:
0.373 moles of ammonium carbonate
Explanation:
To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:
(NH₄)₂CO₃ contains: 2 moles N, 8 moles H, 1 mole C, 3 moles O. Molar mass:
2N = 14.0g/mol*2 = 28.0
8H = 1.0g/mol*8 = 8.0
1C = 12.0g/mol*1 = 12.0
3O = 16.0g/mol*3 = 48.0
Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol
The moles of ammonium carbonate in 35.8g are:
35.8g * (1mol / 96.0g) =
<h3>0.373 moles of ammonium carbonate</h3>
I would go with C. SDS and warning signs
Answer:
The answer is 98.07848. We assume you are converting between grams H2SO4 and mole. You can view more details on each measurement unit: This compound is also known as Sulfuric Acid. The SI base unit for amount of substance is the mole. 1 grams H2SO4 is equal to 0.010195916576195 mole.
<u>Quick conversion chart of moles H2SO3 to grams</u>
1 moles H2SO3 to grams = 82.07908 grams
2 moles H2SO3 to grams = 164.15816 grams
3 moles H2SO3 to grams = 246.23724 grams
4 moles H2SO3 to grams = 328.31632 grams
5 moles H2SO3 to grams = 410.3954 grams
6 moles H2SO3 to grams = 492.47448 grams
7 moles H2SO3 to grams = 574.55356 grams
8 moles H2SO3 to grams = 656.63264 grams
9 moles H2SO3 to grams = 738.71172 grams
10 moles H2SO3 to grams = 820.7908 grams