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denis23 [38]
3 years ago
6

Which of the following apply to gases. Select all that apply.

Chemistry
1 answer:
melamori03 [73]3 years ago
4 0

Explanation:

In gases the molecules are held together by weak Vander waal forces. Due to this they have more kinetic energy and they tend to diffuse at a faster rate because of more number of collisions between the molecules.

That is why, its molecules readily spread into the atmosphere as compared to the molecules of solids and liquids. Also, when molecules of a gas collide with the walls of a container then they tend to come back at their initial position for a fraction of second or more.

Hence, gas collisions are elastic in nature.

According to Graham's law, rate of diffusion of a gas is inversely proportional to the square root of molar mass of the gas. Hence, more is the molecular weight of gas less likely it is able to diffuse into the surroundings.

       \text{Rate of diffusion} \propto \sqrt{\frac{1}{M}}

Thus, we can conclude that following apply to gases.

  • Gas collisions are elastic.
  • Gases mix faster than solids or liquids.
  • Gases with larger molecular weights diffuse slower than gases with lower molecular weights.
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Answer:

I think the answer is X if wrong i´m sorry

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5 0
2 years ago
2. In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] =
notsponge [240]
Kc= concentration  of  product  divided  by  concentration   of  reactant
NO +  NO2  ---->  N2O3

Kc =(N2O3)  /  (No)(NO2)

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3 years ago
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▹ Answer

<em>x¹⁰z¹⁵</em>

▹ Step-by-Step Explanation

x¹²z¹¹/x²z⁴

<u>Reduce</u>

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<u>Calculate</u>

x¹⁰z¹⁵

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Brrunno [24]
First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.

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Then, divide the given amount of substance by the calculated molar mass.
            number of moles = (20 g)(1 mol of CaCO₃/100 g)
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<em>Answer: 0.2 moles</em>
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