Rust would be a compound.
Answer:
Average speed = 8.8 m/s
Average velocity = 8.8 m/s
Explanation:
From the question,
Avearge speed = 2πr/t................ Equation 1
Where r = 14 m, t = 10 s
Constant π = 22/7
Substitute this value into equation 1
Average speed = 2(22/7)(14)/10
Avearge speed = 8.8 m/s.
For a body moving in circular motion, The average speed and average velocity are equal.
Hence,
Average speed = 8.8 m/s
Average velocity = 8.8 m/s
<em><u>One</u></em><em><u> </u></em><em><u>newton</u></em><em><u> </u></em><em><u>force</u></em><em> </em><em>is</em><em> </em><em>defined as t</em><em>h</em><em>e</em><em> </em><em>force</em><em> </em><em>that</em><em> </em><em>is</em><em> necessary to provide a mass of one kilogram with an acceleration of one metre per second per second. One newton is equal to a force of 100,000 dynes in the centimetre-gram-second (CGS) system, or a force of about 0.2248 pound </em><em>i</em><em>n</em><em> </em><em>the</em><em> </em><em>f</em><em>o</em><em>o</em><em>t</em><em>-</em><em>p</em><em>o</em><em>u</em><em>n</em><em>d</em><em>-</em><em> </em><em>s</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em><em> </em><em>system</em><em>.</em>
Answer:
0.20
Explanation:
The box is moving at constant velocity, which means that its acceleration is zero; so, the net force acting on the box is zero as well.
There are two forces acting in the horizontal direction:
- The pushing force: F = 99 N, forward
- The frictional force: , backward, with
coefficient of kinetic friction
m = 50 kg mass of the box
g = 9.8 m/s^2 gravitational acceleration
The net force must be zero, so we have
which we can solve to find the coefficient of kinetic friction: