Malleus, incus, and stapes, respectively, and collectively, as "middle ear ossicles<span>".</span>
B. the distance the star is from Earth
Explanation:
The apparent magnitude of star is a function of its distance from the earth. It is one of the physical properties that is used to study a star.
The apparent magnitude of a star or other astronomical bodies is a measure of their brightness as seen from a location on the earth.
The apparent magnitude of a star depends on:
- Distance of the star from the location on earth.
- luminosity of the star
- the particles along the part of the star and earth that cuts off the light the earth receives.
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Answer: C) 200 N
Explanation:
The force
is defined as:

Where:
is the mass of the object
is the acceleration
Then:

Finally:

Hence, the correct option is C.
Answer:
Protons and neutrons are all attracted to each other as a result - the strong nuclear force. This is an attractive force that only has an effect over a very short range in the nucleus.
Thank you for your question, what you say is true, the gravitational force exerted by the Earth on the Moon has to be equal to the centripetal force.
An interesting application of this principle is that it allows you to determine a relation between the period of an orbit and its size. Let us assume for simplicity the Moon's orbit as circular (it is not, but this is a good approximation for our purposes).
The gravitational acceleration that the Moon experience due to the gravitational attraction from the Earth is given by:
ag=G(MEarth+MMoon)/r2
Where G is the gravitational constant, M stands for mass, and r is the radius of the orbit. The centripetal acceleration is given by:
acentr=(4 pi2 r)/T2
Where T is the period. Since the two accelerations have to be equal, we obtain:
(4 pi2 r) /T2=G(MEarth+MMoon)/r2
Which implies:
r3/T2=G(MEarth+MMoon)/4 pi2=const.
This is the so-called third Kepler law, that states that the cube of the radius of the orbit is proportional to the square of the period.
This has interesting applications. In the Solar System, for example, if you know the period and the radius of one planet orbit, by knowing another planet's period you can determine its orbit radius. I hope that this answers your question.