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Studentka2010 [4]
3 years ago
15

When parallel light rays exit a convex lens, they .

Chemistry
2 answers:
Alexxx [7]3 years ago
6 0
When the parallel light rays exit a convex lens, it comes away or diverge.
Vitek1552 [10]3 years ago
6 0

Converge

I took the assignment

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describe the" fear appeal" and how it's used in public messaging. Give an example or create your own public health message using
Vsevolod [243]
A good example is cigarretes they try to scare you into not smoking by telling you all of the downsides of smoking like lung cancer and i guess that would be fear appeal 
7 0
2 years ago
8. Write a balanced chemical equation showing how you could prepare each of the following salts from an
polet [3.4K]

Answer:

according to my reading

use own words

Explanation:

Salts are combinations of acids and bases. The cation comes from a base and the anion from an acid. Therefore, to make KNO3 we react KOH and HNO3. See how that is done? We write K and add OH to make KOH. We take NO3 and add H to make HNO3.

6 0
2 years ago
Emperical formula of carbon dioxide
Stells [14]

CO2 is the emperical formula of carbon dioxide

6 0
2 years ago
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Which statement is correct? A. pKa is not an indicator of acid strength. B. An acid with a small Ka is stronger than an acid wit
Svetradugi [14.3K]

Answer:

D

Explanation:

Since [pKa = - log Ka]....hence..,the larger the Ka value,the stronger the acid is..so this means that the pKa is vice versa

Saying that the smaller the pKa value..the stronger the acid is.

3 0
3 years ago
Read 2 more answers
If the reduction reaction has a reduction potential of 0.1 V, and the oxidation reaction has a reduction potential of -0.4V, and
aleksley [76]

Answer : The value of ΔG expressed in terms of F is, -1 F

Explanation :

First we have to calculate the standard electrode potential of the cell.

E^o=E^o_{cathode}-E^o_{anode}

or,

E^o=E^o_{reduction}-E^o_{oxidation}

E^o=(0.1V)-(-0.4V)=+0.5V

Now we have to calculate the standard cell potential.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant

E^o = standard e.m.f of cell = +0.5 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times F\times 0.5)

\Delta G^o=-1F

Therefore, the value of ΔG expressed in terms of F is, -1 F

5 0
3 years ago
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