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3 years ago

Find the velocity of a wave that has a wavelength of 2 meters and a frequency of 2.1Hz

Physics

1 answer:

vodomira [7]3 years ago

7 0

It is 4.2 hope i helped

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The left face of a biconvex lens has a radius of curvature of magnitude 11.7 cm, and the right face has a radius of curvature of

SIZIF [17.4K]

Answer:

Explanation:

R1 = + 11.7 cm

R2 = - 18.7 cm

n = 1.52

(a) Use lens maker formula

$\frac{1}{f}=\left ( n-1 \right )\left ( \frac{1}{R_{1}}-\frac{1}{R_{2}} \right )$

$\frac{1}{f}=\left ( 1.52-1 \right )\left ( \frac{1}{11.7}}+\frac{1}{18.7} \right )$

$\frac{1}{f}=\frac{0.52\times 30.4}{218.79}$

f = 13.84 cm

(b)

R1 = + 18.7 cm

R2 = - 11.7 cm

n = 1.52

(a) Use lens maker formula

$\frac{1}{f}=\left ( n-1 \right )\left ( \frac{1}{R_{1}}-\frac{1}{R_{2}} \right )$

$\frac{1}{f}=\left ( 1.52-1 \right )\left ( \frac{1}{18.7}}+\frac{1}{11.7} \right )$

$\frac{1}{f}=\frac{0.52\times 30.4}{218.79}$

f = 13.84 cm

5 0

3 years ago

What is the kinetic energy of an object that has a mass of 50.0kg and a velocity of 18 m/s?

Rom4ik [11]

<h2>Answer </h2>

The kinetic energy is 8100 J.

<u>Explanation</u>

Mass is 50.0kg and velocity is 18 m/s, the kinetic energy is:

As we know the formula of kinetic energy which is K.E = ½ ( mv ^ 2 ),

mass = m = 50.0kg

velocity = v = 18 m / s,

by putting values in the formula,

K.E = ½ ( mv ^ 2 ),

K.E = ½ ( 50kg ) . ( 18 m / s ) ^ 2

K.E = ½ ( 50kg ) . ( 324 ),

=> K.E = 1/2 ( 16200 ),

=> K.E = 16200 / 2,

=> K.E = 8100J.

Hence, the kinetic energy ( K.E ) is 8100 joule ( J ).

7 0

3 years ago

A runner whose mass is 54 kg accelerates from a stop to a speed of 7 m/s in 3 seconds. (A good sprinter can run 100 meters in ab

Darya [45]

Answer:

a. $F=126N$

b. $E_K=1323J$

Explanation:

Given:

$m=54kg$

$v=7 m/s$

$t= 3s$

The runner force average to find given the equations

$F=m*a$

$a=\frac{v}{t}$

$F=m*\frac{v}{t}=54kg*\frac{7m/s}{3s}$

$F=126N$

Work done by the system by this force so

$W=F*d$

$W=E_K$

$E_K=\frac{1}{2}*m*v^2$

$E_K=\frac{1}{2}*54kg*(7m/s)^2$

$E_K=1323J$

6 0

2 years ago

One light-hour is the distance that light travels in an hour. How far is this, in kilometers? (Recall that the speed of light is

ycow [4]

Answer:

B 1.08 BILLION

Explanation:

SEE ATTACHMENT

Download pdf

6 0

2 years ago

A student performed the following steps to find the solution to the equation x^2-2x-15=0 Where did the student go wrong? STEP 1:

AveGali [126]

B. In step 3

They incorrectly solved for x. It should have been x=-3 and x=5

3 0

3 years ago