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bija089 [108]
3 years ago
8

A stationary boat bobs up and down with a period of 2.4 s when it encounters the waves from a moving boat.

Physics
1 answer:
lapo4ka [179]3 years ago
8 0
It seems like the question is asking for the frequency.
Given: 
Time period (T) = 2.4 sec

Frequency (f) =? 

We know that the formula for frequency is:

Frequency (f) = 1/time period (T) 

= 1 / 2.4 s 

= 0.42 Hz. is the frequency for this problem.
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The tension of the string is calculated as follows;

T =  ma  + mg\\\\T = m(a + g)\\\\where;\\\\a \ is \ upward \ acceleration \ of \ the \ sphere\\\\g \ is \ acceleration \ due \ to \ gravity =9.8 \ m/s^2\\\\a = \frac{\Delta V}{\Delta t} = \frac{v- u}{ t} = \frac{4.6 - 2.81 }{2.64} = 0.678 \ m/s^2

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Explanation:

See attachment

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