Langerhans cells exist on the surface of the skin. They help to protect you by keeping dangerous microbes from entering your body. Langerhans cells do this in two very different ways: by protecting your skin from infection and also by stimulating allergic reactions.
Answer:
A. False
B True
C. False
D.False
E. True
F. False
G. False
H. False
I. True
Explanation:
A. False: The system being analyzed consists of the bug and the car. These are the two bodies involved in the collision.
B. True: The system being analyzed consists of the bug and the car
C. False: The magnitudes of the change in velocity are different from the car and the bug. The velocity of the bug changes from 0 to the velocity of the car, while there is no noticeable change in the velocity of the car
D.False: There is barely any change in the momentum of the car since the mass of the bug is very small.
E. True: Since the mass of the bug is small, and was initially at rest, the magnitude of the change in monentum will be large because the new velocity will be that of the car.
F. False: The system being analyzed consists of the bug and the car. Those are the two bodies involved in the collision
G. False: The car barely changes in velocity since the mass of the bug is small.
H. False: The car barely changes in momentum because the collision does not affect its speed so much. on the other hand the momentum change of the bug is large since its mass is small.
I. True: The bug which was initially at rest will begin moving with the velovity of the speeding car, while the car barely changes in its velocity
Explanation:
proton number + neutron number = atomic mass
30 + 35 = 65
Answer:
3.1 s
Explanation:
from the question we are given the the following:
Weight of books (Fb) = 305 N
Push force (Fp) = 516 N
distance (s) = 5.82 m
Angle of force exerted = 32 degrees
acceleration due to gravity (g) = 9.81 m/s^{2}
coefficient of friction Uk= 0.59
time (t) = ?
mass of the book (m) = weight / (g) = 305 / 9.8 = 31 kg
lets first get the net force from the summation of vertical forces
Fnet = Fpush + Fgravity
F net = 516 + 305sin32
F net = 677.6 N
now lets get the acceleration from the summation of the horizontal forces
Fpcos32 - friction force = m x a
Fpcos32 - (Uk x F net) = m x a
516cos32 - (0.59 x 677.6) = 31 x a
37.8 = 31a
a = 1.22m/s^{2}
now that we have our acceleration we can get the time from the equation of motion
s = ut + o.5at^{2}
u ( initial velocity ) = 0 because the box was initially at rest
5.82 = (0 x t ) + (0.5 x 1.22 x t^{2})
5.82 = 0.61t^{2}
t = 3.1 s
Answer:
3.422 m/s^2
Explanation:
A useful relation is ...
v2^2 -v1^2 = 2ad
(25 m/s)^2 -(3 m/s)^2 = 2a(90 m)
(616 m^2/s^2)/(180 m) = a ≈ 3.422 m/s^2
The acceleration is about 3.422 m/s^2.
