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VARVARA [1.3K]
3 years ago
12

Give two reasons why circular water waves decrease in amplitude

Physics
1 answer:
Ronch [10]3 years ago
3 0
1. friction between water molecules
2. the wave spreads out onto a larger and larger area, so per unit area, the energy of the wave goes down
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Answer:

C

Explanation:

it uses a renewable source

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Given a constant acceleration and assuming linear motion, derive equations for velocity and position of a body with respect to t
uysha [10]

Answer:

v = at + u

x = ut+\frac{1}{2}at^{2}+x_{0}

Explanation:

acceleration, a = constant

As we know that acceleration is the rate of change of velocity

a=\frac{dv}{dt}

dv=adt

integrate on both sides

\int dv=\int adt

v = at + u

Where, u is the integrating constant and here it is equal to the initial velocity

Now we know that the rate of change of displacement is called velocity

v = \frac{dx}{dt}

dx=vdt=(u+at) dt

Integrate on both sides

\int dx=\int (u+at) dt

x = ut+\frac{1}{2}at^{2}+x_{0}

where, xo is the integrating constant which is initial position of the particle.

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3 years ago
What is the main difference between a longitudinal wave and a transverse wave? a longitudinal wave travels faster than a transve
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A hammer exerts 49.8 N of force on the head (r=0.00510 m) of a nail. How much pressure does it exert on the nail?
Kisachek [45]

Answer:

609547.12 Pa ≈ 6.10×10^5 Pa

Explanation:

Step 1:

Data obtained from the question. This include the following:

Force (F) = 49.8 N

Radius (r) = 0.00510 m

Pressure (P) =..?

Step 2:

Determination of the area of the head of the nail.

The head of a nail is circular in nature. Therefore, the area is given by:

Area (A) = πr²

With the above formula we can obtain the area as follow:

Radius (r) = 0.00510 m

Area (A) =?

A = πr²

A = π x (0.00510)²

A = 8.17×10^-5 m²

Therefore the area of the head of the nail is 8.17×10^-5 m²

Step 3:

Determination of the pressure exerted by the hammer.

This is illustrated below:

Force (F) = 49.8 N

Area (A) = 8.17×10^-5 m²

Pressure (P) =..?

Pressure (P) = Force (F) /Area (A)

P = F/A

P = 49.8/8.17×10^-5

P = 609547.12 N/m²

Now, we shall convert 609547.12 N/m² to Pa.

1 N/m² = 1 Pa

Therefore, 609547.12 N/m² = 609547.12 Pa.

Therefore, the pressure exerted by the hammer on the nail is 609547.12 Pa or 6.10×10^5 Pa

8 0
4 years ago
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