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Greeley [361]
3 years ago
11

Does the volume of a fixed quantity of gas decrease to half its original value when the temperature is lowered from 100 ∘c to 50

∘c ?
Physics
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

No

Explanation:

Let's assume the gas pressure is constant. Then we can use Charle's law, which states that the volume of the gas is proportional to the absolute temperature (in Kelvin):

\frac{V}{T}=const.

This can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where we have

T_1 = 100^{\circ}+273 =373 K  is the initial temperature of the gas

T_2 = 50^{\circ}+273 =323 K  is the final temperature of the gas

Re-arranging the previous equation, we find

V_2=V_1 \frac{T_2}{T_1}=V_1 \frac{323 K}{373 K}=0.87 V_1

so, the volume of the gas decreases by a factor 0.87.

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Nitrogen and phosphorus !

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Put the waves in order from shortest to longest wavelength
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Answer:

b, a, c

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The middle one has the shortest wavelength, then it's the top one and the last one has the longest wavelength.

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The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter su
balandron [24]

The new period will be 2.486 days.

<h3>What is the period?</h3>

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

The time period for one rotation of the star, T = 20.30 days

D' = 0.350 D

R' = 0.350 R

From the law of conservation of angular momentum;

\rm  I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2  \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2}  \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days

Hence, the new period will be 2.486 days.

To learn more about the period, refer to the link;

brainly.com/question/569003

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8 0
2 years ago
Jemima is running with a velocity of 5m/s. She has a mass of 65kg, what is her kinetic energy?
puteri [66]

Jemima is running with a velocity of 5m/s. She has a mass of 65kg, what is her kinetic energy would be 812.5 Joules.

<h3>What is mechanical energy?</h3>

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

As given in the problem we have to calculate the Kinetic energy of the Jemima,

Kinetic energy = 1/2 ×mass×velocity²

                        =0.5×65×5²

                        =812.5 Joules

Thus, the kinetic energy of the Jemima would be 812.5 Joules.

To learn more about mechanical energy, refer to the link;

brainly.com/question/12319302

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4 0
1 year ago
How do tires help to increase the friction between the tire and the road?
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The teeth and threads creates roughness that increases the friction between the tire and the road. 
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