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mixer [17]
3 years ago
12

How do tires help to increase the friction between the tire and the road?

Physics
2 answers:
DedPeter [7]3 years ago
6 0
Tires stickier, road stickier, car heavier
Ipatiy [6.2K]3 years ago
5 0
The teeth and threads creates roughness that increases the friction between the tire and the road. 
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What is the difference between total distance covered vs. total displacement of the rube goldberg
nirvana33 [79]

Answer:

The deer traveled 1300m + 500m + 300m, for a total distance. The exact same motion, distance and displacement have significantly different values. It tells you the rate at which an object's displacement, or position, changes.

4 0
3 years ago
a bowling ball and a baseball both roll across your foot at the same speed. The bowling ball hurts more
Maru [420]

Answer:

you are right bowling ball has more mass and it is denser than a baseball

Explanation:

5 0
4 years ago
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1. Find an example of electrical energy being converted to light energy.
Svetradugi [14.3K]
Solar energy is the example of electrical energy
6 0
4 years ago
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
NeX [460]

Answer:

h = 2.087 m

Explanation:

Given

m₁ = 3 kg

v₁ = 20 m/s

m₂ = 2 kg

v₂ = - 14 m/s

In a completely inelastic collision the colliding objects stick together after the collision and move together as a single object.

In the given problem, lets assume that the balls of putty are initially moving along the  y  axis, upward direction being the positive  y  direction. And the collision occurs at the origin of the coordinate system.

We can apply the equation

vs = (m₁*v₁ + m₂*v₂) / (m₁ + m₂)  

⇒   vs = (3 kg*20 m/s + 2 kg*(- 14 m/s)) / (3 kg + 2 kg)  

⇒   vs = 6.4 m/s (↑)

To calculate the maximum height  h  attained by the combined system of two balls of putty after the the collision, we use the expression for linear motion under gravity:

vf² = vi² - 2*g*h

where

vf = 0 m/s  

g = 9.81 m/s²

vi = vs = 6.4 m/s

finally we get h:

h = vi² / (2*g)

⇒   h = (6.4 m/s)² / (2*9.81 m/s²) = 2.087 m

6 0
3 years ago
An orbiting meteor has a mass of 5,123,788 g. What is the mass of the meteor in kg?
gavmur [86]

Answer:

5123.79 kg

Explaination:

I did 5,123,788 divided by 1000 and got 5123.788

Then I rounded to the nearest 10th place.

Hope this helps, have a great day!

6 0
3 years ago
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