Answer:
number (12 is c) (13 is 5) (14 is 5)
Explanation:
You can tell if each side of the equation has the same molar mass.
Answer:
200 mL
Explanation:
You simply add the volumes :) If this was a case that involved titration, you would use the formula M1V1 = M2V2. I do not know if that is what you were referring to but based on the information you gave, you simply add the two volumes.
Answer:
C = 18.29 g
Explanation:
Given data:
Mass of beryllium needed = ?
Mass of nitrogen = 18.9 g
Solution:
Chemical equation:
3Be + N₂ → Be₃N₂
now we will calculate the number of moles of nitrogen:
Number of moles = mass/molar mass
Number of moles = 18.9 g/ 28 g/mol
Number of moles = 0.675 mol
Now we will compare the moles of nitrogen and Be from balance chemical equation.
N₂ : Be
1 : 3
0.675 : 3/1×0.675 = 2.03 mol
Number of moles of Be needed are 2.03 mol.
Mass of Beryllium:
Mass = number of moles × molar mass
Mass = 2.03 mol × 9.01 g/mol
Mass = 18.29 g
To measure the density of the stone placed in a graduated cylinder let us follow these steps bellow
- Measure the volume of water poured into a graduated cylinder
- Place the object in the water and remeasure the volume.
- The difference between the two volume measurements is the volume of the object.
- Divide the mass by the volume to calculate the density of the object.
<em>We know that the formula for density is given as </em>
Given data
Mass = 8gram
Initial Volume of water in cylinder = 25mL
Final Volume of water in cylinder = 29mL
Hence the volume of the rock = 29-25 = 4mL
Therefore the density of the rock = 8/4 = 2 g/mL
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