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marishachu [46]
3 years ago
11

The 3 particles of the atom are

Chemistry
1 answer:
fenix001 [56]3 years ago
8 0
The 3 (THREE) particles of the atoms are:
_______________________________________________
          protons, neutrons, and electrons .
__________________________________________________________
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alexandr1967 [171]

Answer:

C, when the ball lands it will have the least amount potential energy.

Explanation:

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3 years ago
Sally has constructed a concentration cell to measure Ksp for MCln. She constructs the cell by adding 2 mL of 0.05 M M(NO3)n to
hram777 [196]

Answer:

0.1056 mole

Explanation:

As Sally knows that the charge on the metal ion is n = +2

$MCl_n=MCl_2$

In that compartment $[M^{n+}]=[m^{2+}]=8.279 \ M$

The volume of the $MCl_n$ taken in that compartment = 6.380 mL

So, the number of moles of $M^{2+} = 8.279 \times 6.380$

                                                      = 52.82 m mol

                                                      = 0.05280 mol

$MCl_n \rightarrow M^{n+}+nCl^-$

But n = 2

Therefore, moles of $Cl^-$ = 2 x moles of $M^{n+}$

                                       = 2 x 0.05282

                                       = 0.1056 mole

3 0
3 years ago
Which of the following is NOT true?
ivanzaharov [21]
B, hope this helps :)
4 0
3 years ago
Read 2 more answers
What is the concentration of a solution that has 15.0 g NaCl dissolved to a total of 750 ml?
Oksana_A [137]

<u>Answer:</u> The concentration of solution is 0.342 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Sodium chloride) = 15 g

Molar mass of sodium chloride = 58.5 g/mol

Volume of solution = 750 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{15g\times 1000}{58.5g/mol\times 750mL}\\\\\text{Molarity of solution}=0.342M

Hence, the concentration of solution is 0.342 M

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3 years ago
Hi lovessssssss <br> Hsnsgehsndgd
Sergio039 [100]
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2 years ago
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