How can the strength of an electromagnet be increased?

Physics

1 answer:

rewona [7]3 years ago

5 0

Answer:

You can make an electromagnet stronger by doing these things: wrapping the coil around a piece of iron (such as an iron nail) adding more turns to the coil. increasing the current flowing through the coil.

Explanation:

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For the chemical reaction below, determine the amount of hi produced when 3.35 g of hydrogen is reacted with 50.75 g of iodine t

ra1l [238]

Molar mass of H₂ = 1.008 × 2 g/mol = 2.016 g/mol 
Molar mass of I₂ = 126.9 × 2 g/mol = 253.8 g/mol 
Molar mass of HI = (1.008 + 126.9) g/mol = 127.9 g/mol

H₂(g) + I₂(g) → 2HI 
Mole ratio H₂ : I₂ : HI = 1 : 1 : 2 

Then the initial number of moles of H₂ = (3.35 g) / (2.016 g/mol) = 1.662 mol 
Initial number of moles of I₂ = (50.75 g) / (253.8 g/mol) = 0.2000 mol < 1.662 mol 
Hence, I₂ is the limiting reactant (limiting reagent). 

Number of moles of I₂ reacted = 0.2000 mol 
Number of moles of HI reacted = (0.2000 mol) × 2 = 0.4000 mol
Mass of HI reacted = (127.9 g/mol) × (0.4000 mol) = 51.16 g

8 0

4 years ago

A number of compounds containing the heavier noble gases, and especially xenon, have been prepared. One of these is xenon hexafl

aalyn [17]

Answer:

The answer is "82.2 torr"

Explanation:

moles of Xe:

$= \frac{0.06}{131.293} \\\\ =0.00045699313 \ \mol$

moles of $F_2$ :

$= \frac{0.0274}{38} \\\\= 0.00072105263\ \ mol$

moles of produced $XeF_2:$

$= 0.00024$

moles of left $Xe$ :

$= 0.00021$

Calculate the Pressure:

$= \frac{(0.08206\times 0.00024 \times 293)}{(.1)} + \frac{(0.08206\times 0.00021 \times 293)}{(.1)} \\\\= 0.10819611 \ \ atm \\\\ = 0.10819611 \times 760 \\\\ = 82.2 \ \ torr$