Answer:
0.444 mol/L
Explanation:
First step is to find the number of moles of oxalic acid.
n(oxalic acid) = 
Now use the molar ratio to find how many moles of NaOH would be required to neutralize
of oxalic acid.
n(oxalic acid): n(potassium hydroxide)
1 : 2 (we get this from the balanced equation)
: x
x = 0.0111 mol
Now to calculate what concentration of KOH that would be in 25 mL of water:

Answer: 2.19x10^25 atoms
Explanation:
Molar Mass of Neon = 20g/mol
1mole(20g) of Neon contains 6.02x10^23 atoms.
Therefore, 7.27x10^2g of Neon will contain x atoms i.e
X atoms = (7.27x10^2x6.02x10^23)/20 = 2.19x10^25 atoms
In an atom there are the same number of protons as electrons to start with. The answer would be 65 aswell.
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