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LenKa [72]
3 years ago
9

Why are the main cables of the Golden Gate Bridge made of numerous smaller cables?

Engineering
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

The main cables of the Golden Gate Bridge are made of numerous smaller cables because by combining several thousand in number of smaller cables, each having a diameter which is approximately the diameter of a pencil, into the required cable diameter dimensions, the flexibility, strength, resistance to cracking, rotation resistance, crushing resistance and fatigue resistance of the main cables are increased, and failure of a few strands in a multi-stranded cable is more likely to be detected before catastrophic failure takes place than in a single cable

The properties of strength and flexibility that the cable provides are required so that the bridge can better cushion the seismic turbulence of the water and strong wind energy at the bay of San Francisco, the location of the bridge

Explanation:

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A 860 kΩ resistor has 34 μA of current. What is the supply voltage for this electric circuit?
Juliette [100K]

Explanation:

first changing kilo ohm to ohm

860000 = 860 kΩ

and change 34 micro ampare to ampare

34 μA=3.4×10^-5

recalling the equation V=I*R

V= 3.4×10^-5×860000

v=29.24

8 0
3 years ago
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A refrigerator operating on the Carnot cycle is used to make ice. Water freezing at 32oF is the cold reservoir. Heat is rejected
Mnenie [13.5K]

Answer:

Explanation:

From the given information:

Water freezing temp. T_L = 32 ^0 \ F

Heat rejected temp T_H = 72 ^0 \ F

Recall that:

The coefficient of performance is:

COP_{ref} = \dfrac{T_L}{T_H - T_L} \\ \\  = \dfrac{32+460}{(72 +460) -(32+460)} \\ \\ =\dfrac{492}{532 -492} \\ \\ = \dfrac{492}{40} \\ \\ COP_{ref} = 12.3

Again:

The efficiency given by COP can be represented by:

COP = \dfrac{Q_L}{W} \\ \\ W = \dfrac{Q_L}{COP} \\ \\ W = \dfrac{2000 \ lbm \times 144 \ Btu/lbm}{12.3} \\ \\ W = 23414.63 \ Btu

Finally; the power input in an hour can be determined by using the formula:

Power= \dfrac{W}{t} \\ \\  Power = \dfrac{23414.63 \ Btu}{ 1 \ hr} \\ \\  Power = \dfrac{23414.634 \times 1055.056 \ J}{1 \times 3600} \\ \\  Power  = 6.86 \ kW

In hp; since 1 kW = 1.34102 hp

6.86kW will be = (6.86 × 1.34102) hp

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7 0
3 years ago
Air at atmospheric pressure and at 300K flows with a velocity of 1.5m/s over a flat plate. The transition from laminar to turbul
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Answer:3.47 m

Explanation:

Given

Temperature(T)=300 K

velocity(v)=1.5 m/s

At 300 K

\mu =1.846 \times 10^{-5} Pa-s

\rho =1.77 kg/m^3

And reynold's number is given by

Re.=\frac{\rho v\time x}{\mu }

5\times 10^5=\frac{1.77\times 1.5\times x}{1.846\times 10^{-5}}

x=\frac{5\times 10^5\times 1.846\times 10^{-5}}{1.77\times 1.5}

x=3.47 m

5 0
4 years ago
section 10.1 describes a man in the middle attack on the diffie-hellman key exhange protocal in which the adversary generates tw
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Answer:

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2. Jane transmit YA to another person called Alex.

3. James intercept YA and transmit YD to jane.

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At this point james and jane thinks they share a secret key but instead james has a secret key k1 to Jane and k2 to alex.

5. Alex transmit another key XA to alex for example.

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