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Mrrafil [7]
3 years ago
14

The removal of an embedded gas from a solid object, as happens when formaldehyde in new carpets and furniture is released into t

he air, is a process known as:
Physics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

"Offgassing"

Explanation:

According to my research on Kinesiology, I can say that based on the information provided within the question the process being described is known as "Offgassing". In other words this process is defined as when something gives off or releases a chemical, especially a harmful one, in the form of a gas into the air..

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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the thermometer has its stem marked in millimeter instead of degree Celsius. the lower fixed point is 30mm and the upper fixed p
Lorico [155]

10°c

Explanation:

Given parameter;

Lower fixed point = 30mm

Upper fixed point = 180mm

Reading = 45mm

Unknown:

The degree celcuis temperature at 45mm = ?

Solution:

To solve this problem we simply compare the mm- scale to the celcius - scale that we know.

The upper fixed point is the boiling point of water

Lower fixed point is the freezing point of water

This shows that both the upper and lower fixed point of both thermometers are the same;

         mm-scale          °c scale

          180mm               100°c

            45mm                x

          30mm                  0°c

Solving;

                     \frac{x - 0}{100 -0} =  \frac{45 - 30 }{180- 30}

   x (150) = 100  x 15

   x = 10°c

learn more:

Temperature scales brainly.com/question/1603430

#learnwithBrainly

 

7 0
3 years ago
Two children hang by their hands from the same tree branch. The branch is straight, and grows out from the tree trunk at an angl
vazorg [7]

Answer:879.29 N-m

Explanation:

Given

mass of first child m_1=44 kg

distance of first child from tree is r_1=1 m

tree is inclined at an angle of \theta =27^{\circ}

mass of second child m_1=27 kg

distance of second child from tree is r_2=2.1 m

Weight of first child=m_1g=431.2 kg

Weight of second child=m_2g=264.6 kg

Torque of first child weight=m_1g\cos \theta \cdot r_1

T_1=44\times 9.8\times \cos 27\times 1=384.202 N-m

Torque of second child weight=m_2g\cos \theta \cdot r_2

T_2=27\times 9.8\times \cos 27\times 2.1=495.096 N-m

Net torque T_{net}=T_1+T_2=384.202+495.096=879.29 N-m

6 0
3 years ago
A long wire is known to have a radius greater than 4.0 mm and to carry a current uniformly distributed over its cross section. i
ollegr [7]

Magnetic field outside it due to long wire is given by

B = \frac{u_o i}{2 \pi r}

Magnetic field due to long wire inside wire at any point

B = \frac{u_o i r}{2 \pi R^2}

Now the ratio of two magnetic field is given by

\frac{B_{in}}{B_{out}} = \frac{r_1/R^2}{1/r_2}

\frac{0.285}{0.200} = \frac{4*10}{R^2}

1.425 = \frac{40}{R^2}

R = 5.3 mm

8 0
3 years ago
A 4.80 Kg watermelon is dropped from rest from the roof of an 18.0 m building. Calculate the work done by gravity on the waterme
Nonamiya [84]

Answer:

Work, W = 846.72 Joules

Explanation:

Given that,

Mass of the watermelon, m = 4.8 kg

It is dropped from rest from the roof of 18 m building. We need to find the work done by the gravity on the watermelon from the roof to the ground. It is same as gravitational potential energy i.e.

W = mgh

W=4.8\ kg\times 9.8\ m/s^2\times 18\ m

W = 846.72 Joules

So, the work done by the gravity on the watermelon is 846.72 Joules. Hence, this is the required solution.

7 0
3 years ago
A hair dryer is basically a duct of constant diameter in which a few layers of electric resistors are placed. A small fan pulls
nekit [7.7K]

Given:

density of air at inlet, \rho_{a} = 1.20 kg/m_{3}

density of air at inlet, \rho_{b} = 1.05 kg/m_{3}

Solution:

Now,

\dot{m} = \dot{m_{a}} = \dot{m_{b}}

\rho_{a} A v_{a} = \rho _{b} Av_{b}                        (1)

where

A = Area of cross section

v_{a} = velocity of air at inlet

v_{b} = velocity of air at outlet

Now, using eqn (1), we get:

\frac{v_{b}}{v_{a}} = \frac{\rho_{a}}{\rho_{b}}

\frac{v_{b}}{v_{a}} = \frac{1.20}{1.05} = 1.14

% increase in velocity = 1.14\times 100 =114%

which is 14% more

Therefore % increase in velocity is 14%

5 0
3 years ago
Read 2 more answers
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