3 years ago

How many grams of carbon are present in 45.0g of CCl4

1 answer:

6 0

Molar Mass of CCl4= 12+4(35.5)=154 g/mol g Carbon= 45.0g/(154 g/mol)=0.292 mole

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mel-nik [20]

(2) three fewer valence electrons is your answer.

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kvasek [131]

Lower than 7 is acid greater than 7 is a base

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IgorC [24]

Answer : The given compound belongs to ether and alcohol.

Explanation :

The chemical formula of the given compound is, $C_5H_{12}O_2$

First we have to calculate the degree of unsaturation.

Formula used:

Degree of unsaturation = $\frac{2C+2+N-X-H}{2}$

where,

C = number of carbon

H = number of hydrogen

N = number of nitrogen

X = number of halogen

Degree of unsaturation = $\frac{2\times 5+2+0-0-12}{2}=0$

The degree of unsaturation is, 0 that means there is no double or triple bond in the compound only single bond is present between the atoms.

Thus, the given compound belongs to ether and alcohol.

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Blababa [14]

the answer you have chosen is correct

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Helen [10]

Hello I a m s o m o n e I n t h e w o r l d

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