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bonufazy [111]
4 years ago
9

A mystery element has three isotopes of the following masses and percent abundances: 93.597 amu at 23.63 % abundance, 96.191 amu

at 30.53 % abundance, and 95.502 amu. What is the exact atomic mass of the mystery element?
Physics
1 answer:
iogann1982 [59]4 years ago
8 0

Answer:

92.397amu

Explanation: The exact amu of the mystery element is obtained by multiplying the relative abundance of each individual isotope by  its respective amu and then summing the results.

The sum of the total relative abundance for all the isotopes should be 100%.

However, the relative abundance of the isotope with 95.502amu is not given; therefore to obtain it we subtract the sum of the known relative abundances from 100% as follows:

Relative abundance of isotope with 95.502amu = 100-(23.63+30.53) = 42.84%

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2.13 x 10^-19 J or 0.53 eV

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cut off wavelength, λo = 700 nm = 700 x 10^-9 m

λ = 400 nm = 400 x 10^-9 m

Use the energy equation

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K =hc\left ( \frac{1}{\lambda } -\frac{1}{\lambda _{0}}\right )

K =6.63\times 10^{-34}\times 3\times 10^{8}\left ( \frac{1}{4\times 10^{-7} } -\frac{1}{7\times 10^{-7}}\right )

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The wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.
DiKsa [7]

From wave speed formula, period is 1.96 × 10^-15  seconds per cycle and the frequency is 5.1 × 10^14 Hertz

<h3>What is Frequency ?</h3>

The frequency of a wave is the number of complete revolution per second made by a vibrating body.

Given that the wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.

(a) In the sodium atom from which this light originated, the period of the simple harmonic motion which was the source of this electromagnetic wave will be found by using the formula

v = λ/T

Where

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Substitute all the parameters

300000000 = 589 × 10^-9/T

T = 589 × 10^-9/300000000

T = 1.96 × 10^-15  seconds per cycle.

(b) The frequency of this light wave is the reciprocal of its period. That is,

F = 1/T

F = 1/1.96 × 10^-15

F = 5.1 × 10^14 Hertz

Therefore, the period of the wave is 1.96 × 10^-15  seconds per cycle and its frequency is 5.1 × 10^14 Hertz

Learn more about Light Wave here: brainly.com/question/10728818

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