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lyudmila [28]
2 years ago
9

WILL GIVE FREE BRAINLIEST EVERYDAY! DO NOT look up answers!! PLEASE FOLLOW DIRECTIONS ON FUTURE QUESTIONS OR WRONG!!! (Branliest

goes to the first person to get the answers right)
Question: What is the purpose of Iodine, its atomic symbol, Atomic mass. And the number of Protons, neutrons, and electrons. (Please Copy & paste the following) Symbol: Atomic Mass: Protons: Neutrons: Electrons:
Chemistry
1 answer:
Maslowich2 years ago
8 0

Answer:

  • <u>Purpose of Iodine:</u>

Iodine plays a vital role in thyroid health. Our thyroid gland, which is located at the base of the front of your neck, helps regulate hormone production. These hormones control your metabolism and heart health.

  • <u>Symbol:</u>

The symbol of Iodine is " I ".

  • <u>Atomic Mass:</u>

Atomic mass of Iodine is 126.90447 u

  • <u>Protons:</u>

No. of protons in Iodine is 53.

  • <u>Neutrons:</u>

No. of neutrons in Iodine is 74.

  • <u>Electrons:</u>

No. of electrons in Iodine is 53.

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chemistry A basketball is inflated to a pressure of 1.10 atm in a 28.0°C garage. What is the pressure of the basketball outside
butalik [34]

Answer : The final pressure of the basketball is, 0.990 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{P_2}=\frac{T_1}{T_2}

where,

P_1 = initial pressure = 1.10 atm

P_2 = final pressure = ?

T_1 = initial temperature = 28.0^oC=273+28.0=301.0K

T_2 = initial temperature = -2.00^oC=273+(-2.00)=271.0K

Now put all the given values in the above equation, we get:

\frac{1.10atm}{P_2}=\frac{301.0K}{271.0K}

P_2=0.990atm

Thus, the final pressure of the basketball is, 0.990 atm

7 0
3 years ago
Please help me I will give you 10 points​
Vaselesa [24]

Answer:

red ig

Explanation:

5 0
2 years ago
Mg+2N=??<br>complete and balance it​
shtirl [24]

Answer:

mg3n2

Explanation:

3 0
3 years ago
Read 2 more answers
A buffer consists of 0.45 M CH3COOH (acetic acid) and 0.35 M CH3COONa. The Ka of acetic acid is 1.8 x 10-5 . a) Calculate the pH
Zigmanuir [339]

Answer:

A) pH of Buffer solution = 4.59

B) pH after 5.0 ml of 2.0 M NaOH have been added to 400 ml of the original    buffer solution = 4.65

Explanation:

This  is the Henderson-Hasselbalch Equation:

 pH = pKa + log\frac{[conjugate base]}{[acid]}

to calculate the pH of the following Buffer solutions.

8 0
3 years ago
Which of the following sets of empirícal formula, molar mass, and molecular formula is correct?
skad [1K]

<em>Answer:</em>

  • The option C is correct.
  • CH4N, 90g, C3H12N3.

<em>Explanation:</em>

                    <em>Option C:</em>

  • The molecular formula is C3H12N3.
  • If we take ratio 3:12:3 that will be equal to 1:4:1 so its empirical formula will be CH4N.
  • The molar mass of molecular formula = (12×3) + (1×12) +( 14×3) = 98 g

                <em>Option A :</em>

  • In option A , molecular and empirical formula are both correct but molar mass is not valid. It should be 169 acc. to molecular formula.

              <em>Option B:</em>

  • In option B, molecular formual is not valid.
  • It should be as C6H16O2
4 0
3 years ago
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