The average speed and kinetic energy of the particles in a gas are proportional to the measured what of the gas

why did Iran experience almost 80 times more deaths in the 20th Century than California, despite having the same seismicity?

Shkiper50 [21]

Answer: poor construction of houses

Explanation:

Majority of the people that died in Iran were as a result of poor building methods coupled with the fact that there was lack of proper regulation.

California experienced a similar earthquake but due to safer construction methods, about three people died.

Due to population boom in Iran and house shortage, this resulted in builders building cheap houses which were not strong enough.

6 0

3 years ago

He angular position of a swinging door is described by θ = 5.00 + 10.0 t + 2.00 t2 [rad]. (a) determine the angular position, an

Inessa05 [86]

(a) The angular position of the door is described by
$\theta(t)=5+10t+2t^2 [rad]$

The angular velocity is given by the derivative of the angular position:
$\omega(t)=10+4t [rad/s]$

While the angular acceleration is given by the derivative of the angular velocity:
$\alpha(t)=4 [rad/s^2]$

We want to find the values of these quantities at time t=3.00 s, so we must substitute t=3.00 s into the expressions for $\theta, \omega, \alpha$ :
$\theta(3.00 s)=5+(10)(3.00 s)+2(3.00s)^2 = 53 rad$
$\omega(3.00 s)=10+4(3.00s)=22 rad/s$
$\alpha(3.00s)=4 rad/s^2$

(b) The door starts from rest, so its initial angular velocity is $\omega_i=0 rad/s$ , and it reaches a final angular velocity of $\omega_f=0.750 rad/s$ with an angular acceleration of $\alpha=0.560 rad/s^2$ . We can find the angular distance covered by the door by using the following relationship:
$2 \alpha \theta = \omega_f^2 - \omega_i^2$
from which we find
$\theta= \frac{\omega_f^2}{2 \alpha}= \frac{(0.750 rad/s)^2}{2 \cdot 0.560 rad/s^2} =0.502 rad$

6 0

3 years ago

A man walks 40m east then 30m north what is the magnitude of the resultant displacement<br>

Zina [86]

Total distance is 70 meters and the Resultant displacement is 50 meters.

3 0

2 years ago

Read 2 more answers

1. In a demonstration, Mr. K stretches a steel wire to a length 1.23 meters and braces both ends so that they are not free to vi

BaLLatris [955]

Answer:

a.241.08 m/s b. 196 Hz c. 392 Hz

Explanation:

a. Determine the speed of waves within the wire.

The frequency of oscillation of the wave in the string, f = nv/2L where n = harmonic number, v = speed of wave in string, L = length of string = 1.23 m.

Since f = 588 Hz which is the 6 th harmonic, n = 6. So, making v subject of the formula, we have

v = 2Lf/n

substituting the values of the variables into v. we have

v = 2 × 1.23 m × 588Hz/6

v = 241.08 m/s

b. Determine the frequency at which the wire will vibrate with the first harmonic wave pattern.

The first harmonic is obtained from f when n = 1,

So, f = v/2L = 241.08 m/s ÷ 1.23m = 196 Hz

c. Determine the frequency at which the wire will vibrate with the second harmonic wave pattern.

The second harmonic f' = 2f = 2 × 196 Hz = 392 Hz

5 0

3 years ago

You will need these materials:

Oksana_A [137]

Answer:

sorry really need points thanks tho

4 0

3 years ago