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VladimirAG [237]
3 years ago
8

1)Typically, atom gain or lose electrons to achieve (1 point)

Physics
2 answers:
solmaris [256]3 years ago
6 0
1)Typically, atom gain or lose electrons to achieve 
I believe the correct answer from the choices listed is option C, a stable electron configuration

2)The formation of an ionic bond involves

I believe the correct answer is A, transfer of electrons since it is electrons that is involved in a chemical reaction.

Flura [38]3 years ago
6 0

<em><u>Question 1:</u></em>

<u>Answer:</u>

C. Stable electronic configuration

<u>Explanation:</u>

According to Lewis, the atom will be stable when it has 8 electrons in its outermost energy level.

Therefore, atoms tend to undergo chemical reactions and form bonds by either losing, gaining or sharing electrons in order to fulfill the condition of having 8 electrons in outermost shell and become stable

<em><u>Question 2:</u></em>

<u>Answer:</u>

A. Transfer of electrons

<u>Explanation:</u>

Electrons are the part of the atom that are involved in bonding. Atoms (except for noble gases) tend to lose, gain or share electrons in order to have 8 electrons in outermost shell and achieve stability.

<u>Now, </u>

1- when an atom loses an electron or more to another atom that gains these electrons, <u>transfer of electrons</u> occur and <u>ionic bond</u> takes place

2- when atoms <u>share an electron or more</u>, a <u>covalent bond</u> occurs

<u>Based on the above</u>, transfer of electrons represents the formation of ionic bond

Hope this helps :)

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The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.0
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Use Coulomb law: F = k * q1*q2 / (r^2), where k = 9.00 * 10^9 N.m^2/C^2

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An automobile with a mass of 1180 kg is traveling at a speed v = [06] ____________________ m/s. a. What is its kinetic energy in
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Complete Question:

An automobile with a mass of 1180 kg is traveling at a speed v =2.51 m/s. What is its kinetic energy in SI units? What speed (m/s) must an 82.7-kg person move to have the same kinetic energy? At what speed (m/s) must is 12.1-g bullet move to have the same kinetic energy? What would be the speed (m/s) of the automobile if its kinetic energy were doubled?

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a) 3717.1 J b) 9.48 m/s c) 783.8 m/s d) 3.55 m/s

Explanation:

a)

  • By definition, the kinetic energy of a mass m with a speed v, is as follows:

      K = \frac{1}{2} * m *v^{2}

  • if m= 1180 Kg, and v= 2.51 m/s, the kinetic energy can be calculated as follows:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 1180 kg*(2.51 m/s)^{2} = 3717.1 J

b)

  • If the kinetic energy must be the same, and m= 82,7 Kg, we can write the following expression:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 82.7 kg*((v)(m/s))^{2} = 3717.1 J

  • We can solve the above equation as follows:

        v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*3717.1J}{82.7kg} } = 9.48 m/s

c)

  • If K remains the same, and m = 12.1 g = 0.0121 kg (in SI units). we can solve for v  as follows:

       v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*3717.1J}{0.0121kg} } = 783.8 m/s

d)

  • Now, if the kinetic energy were doubled, we would have the following equation:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 1180 kg*((v) m/s)^{2} = 3717.1 J * 2 = 7434.2 J

  • We can solve for the new speed v as follows:

        v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*7434.2J}{1180kg} } = 3.55 m/s

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