Question

the molarity of a vinegar solution is 0.90m. calculate the nimber of acetic acis moles is 10 ml of the solution​

Answer 1

Answer:

0.009 mol.

Explanation:

• Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

M = (no. of moles of acetic acid)/(Volume of the solution (L)).

M = 0.9 M, Volume of the solution = 10.0 mL = 0.01 L.

∴ no. of moles of acetic acid = (M)(Volume of the solution (L)) = (0.9 M)(0.01 L) = 0.009 mol.

Answer 2

Answer:

The number of acetic acid moles is 0.0090 in 10 ml of the solution​.

Explanation:

$Molarity=\frac{Moles}{Volume (L)}$

Let the moles acetic acid in vinegar be n.

Molarity of the vinegar solution = 0.90 M

Volume of the vinegar solution = 10 mL = 0.010 L

1 mL = 0.001 L

$0.90M=\frac{n}{0.010 L}$

$n=0.90 M\times 0.010 L=0.0090 mol$

The number of acetic acid moles is 0.0090 in 10 ml of the solution​.