Thee question is incomplete; the complete question is;
Which elements do not strictly follow the octet rule when they appear in the Lewis structure of a molecule?
Select one or more:
A: Chlorine
B: Carbon
C: Hydrogen
D: Sulfur
E: Fluorine
F: Oxygen
Answer:
chlorine
sulphur
Explanation:
The octet rule states that, for atoms to be stable, they must have eight electrons on their outermost shells.
This rule is not strictly followed by some elements such as sulphur and chlorine. The atoms of these elements can sometimes expand their octet by utilizing the d-orbitals found in the third principal energy level and beyond.
These leads to formation of compounds in which the central atom has more than eight electrons in its outermost shell.
<h2>ANSWER:</h2>
Yes, in this group both events "Oddems Family" and "Thirteenth Night" are mutually exclusive.
<h3>Explanation:</h3>
Mutually exclusive is an statistical term which means the probability of occurrence of two separate event at the same time is zero. It means two events can not be occurred simultaneously.
For example, if we roll the deck ant the probability of coming 1 and 6 at the same time is zero and both events do not depends upon each others occurrence.
Hence only one drama can run in theater at one time. So they are mutually exclusive events.
Explanation:
The given reaction equation will be as follows.
![[FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%5Crightleftharpoons%20%5BFe%5E%7B3%2B%7D%5D%20%2B%20%5BSCN%5E%7B-%7D%5D)
Let is assume that at equilibrium the concentrations of given species are as follows.
![[Fe^{3+}] = 8.17 \times 10^{-3}](https://tex.z-dn.net/?f=%5BFe%5E%7B3%2B%7D%5D%20%3D%208.17%20%5Ctimes%2010%5E%7B-3%7D)
M
![[SCN^{-}] = 8.60 \times 10^{-3}](https://tex.z-dn.net/?f=%5BSCN%5E%7B-%7D%5D%20%3D%208.60%20%5Ctimes%2010%5E%7B-3%7D)
M
![[FeSCN^{2+}] = 6.25 \times 10^{-2}](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%3D%206.25%20%5Ctimes%2010%5E%7B-2%7D)
M
Now, first calculate the value of 
as follows.
![K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E%7B-%7D%5D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
= 
= 
Now, according to the concentration values at the re-established equilibrium the value for ![[FeSCN^{2+}]](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D)
will be calculated as follows.
![11.24 \times 10^{-4} = \frac{8.12 \times 10^{-3} \times 7.84 \times 10^{-3}}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=11.24%20%5Ctimes%2010%5E%7B-4%7D%20%3D%20%5Cfrac%7B8.12%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%207.84%20%5Ctimes%2010%5E%7B-3%7D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
![[FeSCN^{2+}] = 5.66 \times 10^{-2}](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%3D%205.66%20%5Ctimes%2010%5E%7B-2%7D)
M
Thus, we can conclude that the concentration of in the new equilibrium mixture is 
M.
2 mol of Sodium hydroxide (NaOH) reacts to form 1 mol of sodium sulfate (Na_2SO_4)
- 1 mol of NaOH produces 1/2 mol sodium sulfate.
3.7moles of Na OH produces
- 1/2(3.7)=1.8mol sodium sulfate
The most common gas in the troposphere is nitrogen.
I hope this helps!
