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emmainna [20.7K]
3 years ago
8

(Science)(image attached)Pls help, due tmr​

Chemistry
2 answers:
Anastasy [175]3 years ago
8 0
The answer would be 4 Wheeler :)
Lelu [443]3 years ago
6 0

Answer:

4-wheeler

Explanation:

I was thinking that you could say this:

My design is that the 4-wheeler will detect, with the help of technology, when something is approaching or you are very close to it. As the object gets closer, it will beep faster and louder. When the 4-wheeler beeps really fast and really loud, it means that you are about to crash or you are in danger. It will stop and launch an airbag so you stay safe. When the 4-wheeler stops, it will make a signal to let people know that you have stopped.

I am so sorry if this wasn't the response that you were looking for.

Hope this helped!

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How many moles are in 4.233X 10^21
krek1111 [17]
0.00702906176 moles
hope this helps :)
6 0
2 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
How many variables are there in science
Sedaia [141]
There are three variables independent, dependent ,and controlled
7 0
3 years ago
Calculate the mass percent of Cl in Freon -112 (C2 Cl4 F2), a CFC refrigerant
Karolina [17]

Answer:

The answer to your question is:  69.6 %

Explanation:

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MW = (12 x 2) + (35.5 x 4) + (19 x 2)

      = 24 + 142 + 38

      = 204 g

                       204 g of C₂Cl₄F₂  -----------------  100%

                       142 g                     -----------------   x

                      x = (142 x 100 ) / 204

                      x = 69.6 %

5 0
3 years ago
Read 2 more answers
If 224 g of iron reacts with oxygen, forming
Likurg_2 [28]

Answer: 208g

Explanation: Since 224 grams produces 96 grams more, then 112 grams will produce 208 grams.

8 0
3 years ago
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