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antiseptic1488 [7]

3 years ago

7

Evaluate the following expressions log^6 6

1 answer:

lys-0071 [83]3 years ago

7 0

$\bf \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\stackrel{\textit{let's use this one}}{\downarrow }}{log_a a^x = x}\qquad \qquad a^{log_a x}=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ log_6(6)\implies log_6(6^1)\implies 1$

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The point (-7,4) is reflected over the line x=-3. Then the resulting point is reflected over the line y=x. Where is the point lo

Ne4ueva [31]

Answer:

(4, 1)

Step-by-step explanation:

Since the first reflection is over the vertical line x=-3, the y-coordinate remains the same. The x-coordinate of A' will make the point (-3, 4) on the line of reflection be the midpoint between A and A':

(-3, 4) = (A +A')/2

2(-3, 4) -A = A' = (-6-(-7), 8 -4) = (1, 4)

The reflection over the line y=x simply interchanges the two coordinate values:

A'' = (4, 1)

3 0

3 years ago

the appalachian trail is a 2,155-mile hiking trail in the eastern United states. You plan to hike the section of the trail that

Anestetic [448]

Step-by-step explanation:

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3 years ago

Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2

Leviafan [203]

we are given

$r(t)=(7t,3cos(t),3sin(t))$

we can find x , y and z

$x=7t,y=3cos(t),z=3sin(t))$

now, we can use arc length formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

now, we can find derivative

$x'=7,y'=-3sin(t),z'=3cos(t))$

now, we can plug values

and we get

$L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt$

$L=\int _{-2}^2\sqrt{7^2+9}dt$

$=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)$

$L=4\sqrt{58}$ ...........Answer

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3 years ago

Jennifer's Flower Shop sells flowers for $1.35 each. Mary's Flower Shop sells a dozen flowers for $15.96. Who has the best deal?

I am Lyosha [343]

Answer:

Mary has the better deal

Step-by-step explanation:

Jennifer's $1.35 * 12 = $16.20

Mary's 12 flowers = $15.96

7 0

3 years ago

Read 2 more answers

m,kjuhytredwsqer5t6y7u8io98uyt5re4wq

Makovka662 [10]

Same!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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3 years ago