Answer:
The work done on the athlete is approximately 2.09 J
Explanation:
From the definition of the work done by a variable force:
and substituting with the function of our problem:
Un movil aumenta su velocidad de 10m/s a 20m/s acelerando uniformemente a razon de 5m/s2 ¿que distancia logro en dicha operacion
1 answer:
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Answer:
Acceleration,
Explanation:
It is given that,
Separation between the protons,
Charge on protons,
Mass of protons,
We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :
So, the acceleration of two isolated protons is . Hence, this is the required solution.
Answer:
t = 0.67 [s]
Explanation:
To solve this problem we must use the following kinematics equation.
Vf = final velocity = 20[m/s]
Vi = initial velocity = 10 [m/s]
a = aceleration = 15 [m/s^2]
Now replacing in the equation we have:
20 = 10 + (15*t)
t = (20-10)/15
t = 0.67 [s]