Extracting saltine from the water.
Answer:
The speed of the animals is 1.64m/s.
Explanation:
Let us work with variables and call the mass of the two rats 
and 
, and the length of the rod 
.
Using the law of conservation of energy, which says the potential energies of the rats must equal their kinetic energies, we know that when the rod swings to the vertical position,
,
solving for 
, we get:
Putting in the values for , , 
, and we get:
Therefore, as the rod swings through the vertical position , the speed of the rats is 1.64 m/s.
Answer:
F = 1250000 N
Explanation:
If you have 50,000 S, by 25 M. It would be calculated to 1,250,000 N.
Answer:
The impulse exerted by one cart on the other has a magnitude of 4 N.s.
Explanation:
Given;
mass of the first cart, m₁ = 2 kg
initial speed of the first car, u₁ = 3 m/s
mass of the second cart, m₂ = 4 kg
initial speed of the second cart, u₂ = 0
Let the final speed of both carts = v, since they stick together after collision.
Apply the principle of conservation of momentum to determine v
m₁u₁ + m₂u₂ = v(m₁ + m₂)
2 x 3 + 0 = v(2 + 4)
6 = 6v
v = 1 m/s
Impulse is given by;
I = ft = mΔv = m(
The impulse exerted by the first cart on the second cart is given;
I = 2 (3 -1 )
I = 4 N.s
The impulse exerted by the second cart on the first cart is given;
I = 4(0-1)
I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).
Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.
D is your answer hope this helps
