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2 years ago

What type of reaction is 3 and 4 ?

Chemistry

2 answers:

lilavasa [31]2 years ago

8 0

Answer:

3 is decomposition

4 is double replacement

Explanation:

In decomposition reactions, a compound (two or more elements) are broken down into singular elements.

Double replacement reactions have two different compounds, one element from a compound switches with another element in the other compound.

Dmitry [639]2 years ago

6 0

Explanation:

3.)

2NaN3(s) → 2Na(s) + 3N2(g)

= Decomposition Reaction

4.)

Ba(NO3)2 + K2SO4 → 2KNO3 + BaSO4

= Double Displacement Reaction

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Answer: .45 moles of CO2, H20,and NaCl

Explanation:

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2 years ago

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1 year ago

In which 2 states of matter can a substance take the shape of its container?

Natasha2012 [34]

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solid and liquid

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2 years ago

Read 2 more answers

Water is flowing in a pipe with a mass flow rate of 100.0 lb/h (M water H,O=18.016). What is the (i) Molar flow rate of H20 (gmo

Arada [10]

Answer:

i) 0,7 molH20/s

ii)11,2 g O/s

iii)1,4 g H/s

Explanation:

i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

$100 \frac{lb}{h}*\frac{453,5g}{1 lb}*\frac{1molH20}{18,016g}*\frac{1h}{3600s}=0,7\frac{molH20}{s}$

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

$100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{1molO}{1molH20}*\frac{16gr}{1molO}*\frac{1h}{3600s}=11,2\frac{gO}{s}$

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):

$100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{2molH}{1molH20}*\frac{1gr}{1molH}*\frac{1h}{3600s}=1,4\frac{gH}{s}$

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2 years ago

The concentration of CI ion in a sample of H,0 is 15.0 ppm. What mass of CI ion is present in 240.0 mL of H,0, which has a densi

Doss [256]

Answer:

Mass of solute = 0.0036 g

Explanation:

Given data:

Concentration of Cl⁻ = 15.0 ppm

Volume of water = 240 mL

Mass of Cl⁻ present = ?

Solution:

1 mL = 1 g

240 mL = 240 g

Formula:

ppm = mass of solute / mass of sample ×1,000,000

by putting values,

15.0 ppm = (mass of solute / 240 g) ×1,000,000

Mass of solute = 15.0 ppm × 240 g / 1,000,000

Mass of solute = 0.0036 g

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2 years ago