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aliya0001 [1]
4 years ago
6

A sample of propane occupies 274 L at 133 kPa and 316K. Find its volume at 98 kPa and 616K.

Chemistry
1 answer:
Dmitriy789 [7]4 years ago
8 0

Answer:

725L

Explanation:

From the question given, we obtained the following information:

V1 = 274L

P1 = 133kPa

T1 = 316k

P2 = 98kPa

T2 = 616K

V2 =?

We can obtain the new volume by doing the following:

P1V1/T1 = P2V2/T2

133 x 274 / 316 = 98x V2 / 616

Cross multiply to express in linear form:

316 x 98 x V2 = 133 x 274 x 616

Divide both side by 316 x 98

V2 = ( 133 x 274 x 616) /316 x 98

V2 = 725L

Therefore, the new volume is 725L

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Which of the following gases is the best choice for inflating a balloon that must remain inflated for a long period of time?
Oliga [24]

Answer:

argon

Explanation:

argon inhibits evaporation, and prevents corrosion

6 0
3 years ago
What is what is the balanced formula equation for Solutions of lead nitrate and lithium chloride
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3 0
4 years ago
What technique is used to separate the Aluminum soda cans?
Diano4ka-milaya [45]

Answer:

Commonly, Overband Magnets are used to separate steel cans and Eddy Current Separators are used to expel and separate aluminium cans; The Aluminium Cans are discarded into general waste, which is then processed.

Explanation:

8 0
3 years ago
A solution contains 35 mL of 1.50M CuSO​ . What is the molarity when the new 4​ volume is 100mL
elena-s [515]

Answer:

0.525 M CuSO

Explanation:

Molarity (M) is the units mol/L. Let's figure out how many moles of CuSO we have:

35 mL = 35/1000 L = 0.035 L

0.035 L * 1.50 mol/L = 0.0525 mol CuSO

Our new volume is 100 mL, so let's first convert this to L:

100 mL = 100/1000 L = 0.100 L

To find the new molarity, divide the number of moles (0.0525 moles) by the number of liters (0.100 L):

0.0525 mol / 0.100 L = 0.525 M CuSO

Hope this helps!

4 0
3 years ago
What is the mass in grams of the following measurements? 1.00 mol Al ___________ 6.02 x 10 23atoms Al ___________
omeli [17]

Answer:

Mass of 1 mole of Aluminium = Mass of 6.02 x 10 23atoms of Aluminium =  26.98 grams.

Explanation:

1 mole of any element or molecule has 6.02 x 10 23atoms or subparts.

Hence 1 mole of aluminum will also have 6.02 x 10 23atoms. Hence, it is clear that mass of 1 mole of Aluminium will be equal to 6.02 x 10 23atoms of Aluminium.

Thus,

Mass of 1 mole of Aluminium = Mass of 6.02 x 10 23atoms of Aluminium =  26.98 grams.

6 0
3 years ago
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