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2 years ago

What is the action force responsible for sea floor spread?

2 answers:

8 0

Answer: The motivating force for seafloor spreading ridges is tectonic plate slab pull at subduction zones, rather than magma pressure, although there is typically significant magma activity at spreading ridges. ... At a spreading center, basaltic magma rises up the fractures and cools on the ocean floor to form new seabed.

Explanation: Hope This Is Helpful

ollegr [7]2 years ago

4 0

Answer:

Seafloor spreading helps explain continental drift in the theory of plate tectonics. When oceanic plates diverge, tensional stress causes fractures to occur in the lithosphere. The motivating force for seafloor spreading ridges is tectonic plate slab pull at subduction zones, rather than magma pressure

Explanation:

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A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °C and dropped into 42 g of water (with an

professor190 [17]

Answer:

1.717 J/g °C ( third option)

Explanation:

A piece of the unknown metal dropped into water this means that Q of metal is equal to Q of the water. We write this equality as follows:

Step 1: writing the formulas:

Q = mc∆T

⇒ -Q(metal) = Q(water) Because :Metal dropped into water this means that Q of metal is equal to Q of the water.

We can write the formula different :

Mass of metal * (cmetal)(ΔT) = Mass of water *(cwater) (ΔT)

⇒ Here c is the specific heat and depends on material and phase

For this case :

mass of the metal = 68.6g

mass of the water = 42g

Specific heat of the metal = TO BE DETERMINED

Specific heat of the water = 4.184J/g °C

Initial temperature of the metal = 100 °C ⇒ Change of temperature: 52.1 - 100

Initial temperature of the water = 20°C ⇒ Change of temperature: 52.1 - 20

Step 2: Calculating specific heat of the metal

-(Mass of metal) * (cmetal)*(ΔT)) = (Mass of water) *(cwater)*(ΔT)

-68.6g (cmetal)(52.1 - 100) = 42g (4.184j/g °C) (52.1 - 20)

-68.6g *cmetal * (-47.9) = 42g (4.184j/g °C) *(32.1)

3285.94 * cmetal = 5640.87

cmetal = 5640.87 / 3285.94 = 1,71667 J/g °C

cMetal = 1.717 J/g °C

4 0

2 years ago

Which of these cause the build up of volcanic landforms?

finlep [7]

D. ash, cinder, and lava

6 0

2 years ago

Read 2 more answers

If equal volumes of 0.1 M HCl and 0.2 M TRIS (base form) are mixed together. The pKa of TRIS is 8.30. Which of the following sta

blondinia [14]

Answer:

option D is correct

D. This solution is a good buffer.

Explanation:

TRIS (HOCH $_{2}$ ) $_{3}$ CNH $_{2}$

if TRIS is react with HCL it will form salt

(HOCH $_{2}$ ) $_{3}$ CNH $_{2}$ + HCL ⇆ (HOCH $_{2}$ ) $_{3}$ NH $_{3}$ CL

Let the reference volume is 100

Mole of TRIS is = 100 × 0.2 = 20

Mole of HCL is = 100 × 0.1 = 10

In the reaction all of the HCL will Consumed,10 moles of the salt will form

and 10 mole of TRIS will left

hence , Final product will be salt +TRIS(9 base)

H = Pk $_{a}$ + log (base/ acid)

8.3 + log(10/10)

8.3

6 0

3 years ago

7. Calculate the amount of energy required heat 100.g to H2O(s) changes to H2O(l) at 0°C

Brrunno [24]

Answer:

33300J

Explanation:

Given parameters:

Mass of ice = 100g

Unknown:

Amount of energy = ?

Solution:

This is a phase change process from solid to liquid. In this case, the latent heat of melting of ice is 3.33 x 10⁵ J/kg.

So;

H = mL

m is the mass

L is the latent heat of melting ice

Now, insert the parameters and solve;

H = mL

mass from gram to kilogram;

100g gives 0.1kg

H = 0.1 x 3.33 x 10⁵ = 33300J

8 0

2 years ago

A solution is prepared by diluting 6.0 mL of a 7.6 x 10-4 g/mL solution to a total volume

MissTica

Answer:

4.56 X 10^ -4 g/mL

Explanation:

A solution is prepared by diluting 6.0 mL of a 7.6 x 10-4 g/mL solution to a total volume of 10.0 mL. Calculate the concentration of the dilute solution.

(7.6 X10^-4 gm/m L) x( 6.0 m L ) = 45.6 X 10^-4 g

this is dissolved )in 10 m L=45.6 X 10^-4 g/ 10

4.56 X 10^ -4 g/mL

check

6/10 =0.6

4.56/7.6 = o.,6

4 0

2 years ago