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3 years ago

9.69×10^25 formula units of iron(III) nitrate is equal to how many moles of Fe(NO3)3?

Chemistry

1 answer:

scoray [572]3 years ago

6 0

Answer:

160.9 mol ≅ 161.0 mol.

Explanation:

It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms (formula units).

Using cross multiplication:

1.0 mole of Fe(NO₃)₃ contains → 6.022 x 10²³ formula units.

??? mole of Fe(NO₃)₃ contains → 9.69 x 10²⁵ formula units.

<em>∴ The no. of moles of He contains (9.69 x 10²⁵ formula units)</em> = (1.0 mol)(9.69 x 10²⁵ formula units.)/(6.022 x 10²³ formula units) = <em>160.9 mol ≅ 161.0 mol.</em>

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3 years ago

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3 years ago

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Dima020 [189]

The amount of sugar is 2621 mg

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A 12.630 g milk chocolate bar is found to contain 8.315 g of sugar.

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Now, we have to determine the amount of sugar in milligrams if we had a chocolate bar with 4.000 g:

$4.000gChocolate*\frac{658.35mgSugar}{1gChocolate}=2621mgSugar$

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3 years ago

Which of the following mixtures may be act as a buffer solution?

lions [1.4K]

Answer:

B) HF, NaF

Explanation:

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The buffer would have the weak acid HF and its conjugate base, F- which comes from the soluble salt NaF.

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