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tatuchka [14]
3 years ago
13

9.69×10^25 formula units of iron(III) nitrate is equal to how many moles of Fe(NO3)3?

Chemistry
1 answer:
scoray [572]3 years ago
6 0

Answer:

160.9 mol ≅ 161.0 mol.

Explanation:

  • It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms (formula units).

Using cross multiplication:

1.0 mole of Fe(NO₃)₃ contains → 6.022 x 10²³ formula units.

??? mole of Fe(NO₃)₃ contains → 9.69 x 10²⁵ formula units.

<em>∴ The no. of moles of He contains (9.69 x 10²⁵ formula units)</em> = (1.0 mol)(9.69 x 10²⁵ formula units.)/(6.022 x 10²³ formula units) = <em>160.9 mol ≅ 161.0 mol.</em>

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1) The amount of PbS produced will be 16.27 grams

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1) The equation is balanced. The mole ratio of lead (II) acetate to the PbS is 1:1.

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