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larisa86 [58]
3 years ago
14

Which traits explain the differences between halogens and alkali metals? Select all that apply Question 5 options: Halogens are

better oxidizing agents than their alkali metal counterparts within the same period. Halogens have a larger van der Waal's radii than their alkali metal counterparts within the same period. Halogens have a higher effective nuclear charge than their alkali metal counterparts within the same period. Halogens have a higher first ionization energy than their alkali metal counterparts within the same period. Halogens have a higher electron affinity than their alkali metal counterparts within the same period.
Chemistry
1 answer:
o-na [289]3 years ago
3 0

Answer:

Halogens are better oxidizing agents than their alkali metal counterparts within the same period

Halogens have a higher first ionization energy than their alkali metal counterparts within the same period.

Halogens have a higher electron affinity than their alkali metal counterparts within the same period.

Halogens have a higher effective nuclear charge than their alkali metal counterparts within the same period

Explanation:

Effective nuclear charge increases across a period and accounts for increase in ionization energy across a period. This explains why halogens in the same period with alkali metals have higher effective bucket charge as well as ionization energy than the alkali metals.

Similarly, electron affinity increased across a period, halogens have greater ekctron affinity than corresponding alkali metals in the same period.

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How many electrons and protons are contained in an atom of arsenic
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2.998x10^8 m/s is how many kilometers per hour
Alex

1.079 x 10⁹ km/h

<h3>Further explanation</h3>

2.998 x 10⁸ m/s has been known as the speed of light.

Let us convert the unit m/s to km/hour.

Change in unit length:

If 1 km = 1,000 cm, then \boxed{ \ 1 \ cm = 0.001 \ km \ } \rightarrow \boxed{ \ 1 \ cm = 10^{-3} \ km \ }

Change in unit time:

If \boxed{ \ 1 \ hour = 60 \ minutes = 3,600 \ seconds \ }, then \boxed{ \ 1 \ second = \frac{1}{3,600} \ hours \ }

The Process:

\boxed{ \ 2.998 \times 10^8 \ \frac{m}{s} \times \frac{10^{-3} \ km}{1 \ m} \times \frac{1 \ s}{\frac{1}{3,600} \ hours} \ }

\boxed{ \ 2.998 \times 10^8 \times 10^{-3} \ km \times \frac{3,600}{hours} \ }

\boxed{ \ 10,792.8 \10 \times 10^5 \ \frac{km}{hour} \ }

Remember, we must write the results in scientific notation, i.e.,

\boxed{\ a \times 10^b \ } \rightarrow \boxed{ \ 1 \leq a < 10 \ } \rightarrow \boxed{ \ b \ must \ be \ an \ integer \ }

Thus the result of unit conversion is

\boxed{ \ \boxed{ \ 2.998 \times 10^8 \ m/s \ } \rightarrow \boxed{ \ 1.079 \times 10^9 \ km/h} \ }

<h3>Learn more</h3>
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Keywords: speed of light, convert, m/s to km/h, unit length, time, hours, minutes, second, scientific notation

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