Answer:
a. Boron trifluoride
b. Propane
c. Dinitrogen pentoxide
d. Carbon Dioxide
e. Silicon Octafluroride?
Answer:
190 g
Explanation:
Knowing that:
- O₂ gas in air: 0.28 g O₂ / L of air
- Air inhaled at rest: 19.3 fl.oz. air / breath
- Human takes 20 breaths / min
The grams of oxygen gas (O₂) that a human at rest inhales in 1 hour (60 minutes) will be calculated as:
grams of O₂ = breaths in 1 hour * air inhaled per breath * amount of O₂ in air

grams of O₂ = 191.78 g
190 g of O₂ are inhaled in 1 hour (written in correct number of significant figures)
*In the calculation the amount of air inhaled per breath was converted from fl.oz. to Liters knowing that <em>1 L = 33.814 fl.oz.</em>
Th absolute pressure is measured relative to the absolute zero pressure
Respuesta:
14,9 g
Explicación:
Paso 1: Calcular los moles de gas
Una garrafa contiene 9 L de gas a 18°C (291 K) y 780 Torr. Podemos encontrar los moles de gas (n) usando la ecuación del gas ideal.
P × V = n × R × T
n = P × V/R × T
n = 780 torr × 9 L/(62,4 Torr.L/mol.K)/ × 291 K = 0.387 mol
Paso 2: Calcular la masa molar del gas
El gas tiene una densidad (ρ) de 2 g/L a 80 °C (353 K) y 1,5 atm. Podemos calcular la masa molar (M) del gas usando la siguiente fórmula.
ρ = P × M / R × T
M = ρ × R × T / P
M = 2 g/L × (0.082 atm.L/mol.K) × 353 K / 1,5 atm = 38,59 g/mol
Paso 3: Calcular la masa del gas (m)
Usaremos la siguiente formula.
m = n × M = 0.387 mol × 38,59 g/mol = 14,9 g